MAYBE

Problem:
 f(f(0(),x),1()) -> f(g(f(x,x)),x)
 f(g(x),y) -> g(f(x,y))

Proof:
 DP Processor:
  DPs:
   f#(f(0(),x),1()) -> f#(x,x)
   f#(f(0(),x),1()) -> f#(g(f(x,x)),x)
   f#(g(x),y) -> f#(x,y)
  TRS:
   f(f(0(),x),1()) -> f(g(f(x,x)),x)
   f(g(x),y) -> g(f(x,y))
  Open