YES Problem: 1(2(1(x1))) -> 2(0(2(x1))) 0(2(1(x1))) -> 1(0(2(x1))) L(2(1(x1))) -> L(1(0(2(x1)))) 1(2(0(x1))) -> 2(0(1(x1))) 1(2(R(x1))) -> 2(0(1(R(x1)))) 0(2(0(x1))) -> 1(0(1(x1))) L(2(0(x1))) -> L(1(0(1(x1)))) 0(2(R(x1))) -> 1(0(1(R(x1)))) Proof: DP Processor: DPs: 1#(2(1(x1))) -> 0#(2(x1)) 0#(2(1(x1))) -> 0#(2(x1)) 0#(2(1(x1))) -> 1#(0(2(x1))) L#(2(1(x1))) -> 0#(2(x1)) L#(2(1(x1))) -> 1#(0(2(x1))) L#(2(1(x1))) -> L#(1(0(2(x1)))) 1#(2(0(x1))) -> 1#(x1) 1#(2(0(x1))) -> 0#(1(x1)) 1#(2(R(x1))) -> 1#(R(x1)) 1#(2(R(x1))) -> 0#(1(R(x1))) 0#(2(0(x1))) -> 1#(x1) 0#(2(0(x1))) -> 0#(1(x1)) 0#(2(0(x1))) -> 1#(0(1(x1))) L#(2(0(x1))) -> 1#(x1) L#(2(0(x1))) -> 0#(1(x1)) L#(2(0(x1))) -> 1#(0(1(x1))) L#(2(0(x1))) -> L#(1(0(1(x1)))) 0#(2(R(x1))) -> 1#(R(x1)) 0#(2(R(x1))) -> 0#(1(R(x1))) 0#(2(R(x1))) -> 1#(0(1(R(x1)))) TRS: 1(2(1(x1))) -> 2(0(2(x1))) 0(2(1(x1))) -> 1(0(2(x1))) L(2(1(x1))) -> L(1(0(2(x1)))) 1(2(0(x1))) -> 2(0(1(x1))) 1(2(R(x1))) -> 2(0(1(R(x1)))) 0(2(0(x1))) -> 1(0(1(x1))) L(2(0(x1))) -> L(1(0(1(x1)))) 0(2(R(x1))) -> 1(0(1(R(x1)))) Matrix Interpretation Processor: dim=3 interpretation: [L#](x0) = [1 0 0]x0, [0#](x0) = [1 0 0]x0, [1#](x0) = [1 0 0]x0, [0 1 1] [0] [R](x0) = [1 0 1]x0 + [1] [1 1 0] [1], [0 0 0] [1] [L](x0) = [1 0 0]x0 + [1] [0 0 0] [0], [0 0 0] [1] [0](x0) = [0 0 0]x0 + [1] [1 0 0] [0], [1 1 1] [2](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [0] [1](x0) = [0 0 0]x0 + [1] [0 1 1] [1] orientation: 1#(2(1(x1))) = [1 1 1]x1 + [2] >= [1 1 1]x1 = 0#(2(x1)) 0#(2(1(x1))) = [1 1 1]x1 + [2] >= [1 1 1]x1 = 0#(2(x1)) 0#(2(1(x1))) = [1 1 1]x1 + [2] >= [1] = 1#(0(2(x1))) L#(2(1(x1))) = [1 1 1]x1 + [2] >= [1 1 1]x1 = 0#(2(x1)) L#(2(1(x1))) = [1 1 1]x1 + [2] >= [1] = 1#(0(2(x1))) L#(2(1(x1))) = [1 1 1]x1 + [2] >= [1] = L#(1(0(2(x1)))) 1#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 1#(x1) 1#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 0#(1(x1)) 1#(2(R(x1))) = [2 2 2]x1 + [2] >= [0 1 1]x1 = 1#(R(x1)) 1#(2(R(x1))) = [2 2 2]x1 + [2] >= [0 1 1]x1 = 0#(1(R(x1))) 0#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 1#(x1) 0#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 0#(1(x1)) 0#(2(0(x1))) = [1 0 0]x1 + [2] >= [1] = 1#(0(1(x1))) L#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 1#(x1) L#(2(0(x1))) = [1 0 0]x1 + [2] >= [1 0 0]x1 = 0#(1(x1)) L#(2(0(x1))) = [1 0 0]x1 + [2] >= [1] = 1#(0(1(x1))) L#(2(0(x1))) = [1 0 0]x1 + [2] >= [1] = L#(1(0(1(x1)))) 0#(2(R(x1))) = [2 2 2]x1 + [2] >= [0 1 1]x1 = 1#(R(x1)) 0#(2(R(x1))) = [2 2 2]x1 + [2] >= [0 1 1]x1 = 0#(1(R(x1))) 0#(2(R(x1))) = [2 2 2]x1 + [2] >= [1] = 1#(0(1(R(x1)))) [1 1 1] [2] [1 1 1] [2] 1(2(1(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [0] = 2(0(2(x1))) [0 0 0] [1] [0 0 0] [0] [0 0 0] [1] [0 0 0] [1] 0(2(1(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = 1(0(2(x1))) [1 1 1] [2] [1 1 1] [2] [0 0 0] [1] [1] L(2(1(x1))) = [1 1 1]x1 + [3] >= [2] = L(1(0(2(x1)))) [0 0 0] [0] [0] [1 0 0] [2] [1 0 0] [2] 1(2(0(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [0] = 2(0(1(x1))) [0 0 0] [1] [0 0 0] [0] [2 2 2] [2] [0 1 1] [2] 1(2(R(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [0] = 2(0(1(R(x1)))) [0 0 0] [1] [0 0 0] [0] [0 0 0] [1] [0 0 0] [1] 0(2(0(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = 1(0(1(x1))) [1 0 0] [2] [1 0 0] [2] [0 0 0] [1] [1] L(2(0(x1))) = [1 0 0]x1 + [3] >= [2] = L(1(0(1(x1)))) [0 0 0] [0] [0] [0 0 0] [1] [0 0 0] [1] 0(2(R(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = 1(0(1(R(x1)))) [2 2 2] [2] [0 1 1] [2] problem: DPs: TRS: 1(2(1(x1))) -> 2(0(2(x1))) 0(2(1(x1))) -> 1(0(2(x1))) L(2(1(x1))) -> L(1(0(2(x1)))) 1(2(0(x1))) -> 2(0(1(x1))) 1(2(R(x1))) -> 2(0(1(R(x1)))) 0(2(0(x1))) -> 1(0(1(x1))) L(2(0(x1))) -> L(1(0(1(x1)))) 0(2(R(x1))) -> 1(0(1(R(x1)))) Qed