YES

Problem:
 p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))

Proof:
 DP Processor:
  DPs:
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
   p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
  TRS:
   p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
  EDG Processor:
   DPs:
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
   TRS:
    p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
   graph:
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0)) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(b(x2),a(a(b(x1))))
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0) ->
    p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
   SCC Processor:
    #sccs: 1
    #rules: 2
    #arcs: 6/9
    DPs:
     p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
     p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(x3,x0)
    TRS:
     p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
    Arctic Interpretation Processor:
     dimension: 1
     interpretation:
      [p#](x0, x1) = 1x0 + 1x1 + 0,
      
      [p](x0, x1) = 1x0 + 1x1 + 2,
      
      [b](x0) = x0 + 0,
      
      [a](x0) = x0 + 0
     orientation:
      p#(p(b(a(x0)),x1),p(x2,x3)) = 2x0 + 2x1 + 2x2 + 2x3 + 3 >= 2x0 + 2x1 + 2x2 + 2x3 + 3 = p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
      
      p#(p(b(a(x0)),x1),p(x2,x3)) = 2x0 + 2x1 + 2x2 + 2x3 + 3 >= 1x0 + 1x3 + 0 = p#(x3,x0)
      
      p(p(b(a(x0)),x1),p(x2,x3)) = 2x0 + 2x1 + 2x2 + 2x3 + 3 >= 2x0 + 2x1 + 2x2 + 2x3 + 3 = p(p(b(x2),a(a(b(x1)))),p(x3,x0))
     problem:
      DPs:
       p#(p(b(a(x0)),x1),p(x2,x3)) -> p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
      TRS:
       p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
     Matrix Interpretation Processor: dim=3
      
      interpretation:
       [p#](x0, x1) = [0 1 0]x0 + [1 1 0]x1,
       
                     [0 0 0]     [0 0 1]     [0]
       [p](x0, x1) = [0 1 1]x0 + [1 1 0]x1 + [1]
                     [0 0 0]     [0 0 0]     [0],
       
                 [1 0 0]     [1]
       [b](x0) = [0 0 1]x0 + [0]
                 [0 1 0]     [0],
       
                 [0 0 0]     [0]
       [a](x0) = [1 0 0]x0 + [0]
                 [1 1 1]     [1]
      orientation:
       p#(p(b(a(x0)),x1),p(x2,x3)) = [2 1 1]x0 + [1 1 0]x1 + [0 1 1]x2 + [1 1 1]x3 + [3] >= [1 1 1]x0 + [0 1 1]x2 + [0 1 1]x3 + [2] = p#(p(b(x2),a(a(b(x1)))),p(x3,x0))
       
                                    [0 0 0]     [0 0 0]     [0 0 0]     [0 0 0]     [0]    [0 0 0]     [0 0 0]     [0 0 0]     [0]                                   
       p(p(b(a(x0)),x1),p(x2,x3)) = [2 1 1]x0 + [1 1 0]x1 + [0 1 1]x2 + [1 1 1]x3 + [4] >= [1 1 1]x0 + [0 1 1]x2 + [0 1 1]x3 + [3] = p(p(b(x2),a(a(b(x1)))),p(x3,x0))
                                    [0 0 0]     [0 0 0]     [0 0 0]     [0 0 0]     [0]    [0 0 0]     [0 0 0]     [0 0 0]     [0]                                   
      problem:
       DPs:
        
       TRS:
        p(p(b(a(x0)),x1),p(x2,x3)) -> p(p(b(x2),a(a(b(x1)))),p(x3,x0))
      Qed