YES Problem: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Proof: DP Processor: DPs: le#(s(X),s(Y)) -> le#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) TDG Processor: DPs: le#(s(X),s(Y)) -> le#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) graph: quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) -> quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) -> quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) quot#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),Y) -> le#(s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) -> minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) -> minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) -> ifMinus#(false(),s(X),Y) -> minus#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) -> le#(s(X),s(Y)) -> le#(X,Y) le#(s(X),s(Y)) -> le#(X,Y) -> le#(s(X),s(Y)) -> le#(X,Y) SCC Processor: #sccs: 3 #rules: 4 #arcs: 9/36 DPs: quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) KBO Processor: argument filtering: pi(0) = [] pi(le) = 0 pi(true) = [] pi(s) = [0] pi(false) = [] pi(minus) = 0 pi(ifMinus) = 1 pi(quot) = [0] pi(quot#) = 0 weight function: w0 = 1 w(quot#) = w(quot) = w(false) = w(s) = w(true) = w(0) = 1 w(ifMinus) = w(minus) = w(le) = 0 precedence: 0 > quot > quot# ~ ifMinus ~ minus ~ false ~ s ~ true ~ le problem: DPs: TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Qed DPs: minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(minus#) = 0 pi(ifMinus#) = 1 problem: DPs: minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) SCC Processor: #sccs: 0 #rules: 0 #arcs: 2/1 DPs: le#(s(X),s(Y)) -> le#(X,Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(le#) = 1 problem: DPs: TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Qed