YES

Problem:
 f(g(h(x,y)),f(a(),a())) -> f(h(x,x),g(f(y,a())))

Proof:
 DP Processor:
  DPs:
   f#(g(h(x,y)),f(a(),a())) -> f#(y,a())
   f#(g(h(x,y)),f(a(),a())) -> f#(h(x,x),g(f(y,a())))
  TRS:
   f(g(h(x,y)),f(a(),a())) -> f(h(x,x),g(f(y,a())))
  EDG Processor:
   DPs:
    f#(g(h(x,y)),f(a(),a())) -> f#(y,a())
    f#(g(h(x,y)),f(a(),a())) -> f#(h(x,x),g(f(y,a())))
   TRS:
    f(g(h(x,y)),f(a(),a())) -> f(h(x,x),g(f(y,a())))
   graph:
    
   Qed