YES

Problem:
 f(g(f(a()),h(a(),f(a())))) -> f(h(g(f(a()),a()),g(f(a()),f(a()))))

Proof:
 DP Processor:
  DPs:
   f#(g(f(a()),h(a(),f(a())))) -> f#(h(g(f(a()),a()),g(f(a()),f(a()))))
  TRS:
   f(g(f(a()),h(a(),f(a())))) -> f(h(g(f(a()),a()),g(f(a()),f(a()))))
  EDG Processor:
   DPs:
    f#(g(f(a()),h(a(),f(a())))) -> f#(h(g(f(a()),a()),g(f(a()),f(a()))))
   TRS:
    f(g(f(a()),h(a(),f(a())))) -> f(h(g(f(a()),a()),g(f(a()),f(a()))))
   graph:
    
   Qed