MAYBE

Problem:
 f(y,f(y,x)) -> f(f(a(),y),f(a(),y))

Proof:
 DP Processor:
  DPs:
   f#(y,f(y,x)) -> f#(a(),y)
   f#(y,f(y,x)) -> f#(f(a(),y),f(a(),y))
  TRS:
   f(y,f(y,x)) -> f(f(a(),y),f(a(),y))
  Arctic Interpretation Processor:
   dimension: 1
   interpretation:
    [f#](x0, x1) = x0 + x1 + 0,
    
    [a] = 3,
    
    [f](x0, x1) = 1x0 + 1x1 + 4
   orientation:
    f#(y,f(y,x)) = 1x + 1y + 4 >= y + 3 = f#(a(),y)
    
    f#(y,f(y,x)) = 1x + 1y + 4 >= 1y + 4 = f#(f(a(),y),f(a(),y))
    
    f(y,f(y,x)) = 2x + 2y + 5 >= 2y + 5 = f(f(a(),y),f(a(),y))
   problem:
    DPs:
     f#(y,f(y,x)) -> f#(f(a(),y),f(a(),y))
    TRS:
     f(y,f(y,x)) -> f(f(a(),y),f(a(),y))
   Open