MAYBE

Problem:
 f(y,f(x,y)) -> f(f(a(),y),f(a(),x))

Proof:
 DP Processor:
  DPs:
   f#(y,f(x,y)) -> f#(a(),x)
   f#(y,f(x,y)) -> f#(a(),y)
   f#(y,f(x,y)) -> f#(f(a(),y),f(a(),x))
  TRS:
   f(y,f(x,y)) -> f(f(a(),y),f(a(),x))
  Arctic Interpretation Processor:
   dimension: 1
   interpretation:
    [f#](x0, x1) = -1x1 + 0,
    
    [a] = 1,
    
    [f](x0, x1) = 1x0 + 1x1 + 3
   orientation:
    f#(y,f(x,y)) = x + y + 2 >= -1x + 0 = f#(a(),x)
    
    f#(y,f(x,y)) = x + y + 2 >= -1y + 0 = f#(a(),y)
    
    f#(y,f(x,y)) = x + y + 2 >= x + 2 = f#(f(a(),y),f(a(),x))
    
    f(y,f(x,y)) = 2x + 2y + 4 >= 2x + 2y + 4 = f(f(a(),y),f(a(),x))
   problem:
    DPs:
     f#(y,f(x,y)) -> f#(f(a(),y),f(a(),x))
    TRS:
     f(y,f(x,y)) -> f(f(a(),y),f(a(),x))
   Open