YES Problem: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) Proof: DP Processor: DPs: a#(b(x1)) -> a#(x1) a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> b#(a(c(a(x1)))) c#(c(c(x1))) -> b#(x1) TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) TDG Processor: DPs: a#(b(x1)) -> a#(x1) a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> b#(a(c(a(x1)))) c#(c(c(x1))) -> b#(x1) TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) graph: a#(b(x1)) -> c#(a(x1)) -> c#(c(c(x1))) -> b#(x1) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> b#(a(c(a(x1)))) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> a#(x1) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> b#(a(c(a(x1)))) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> a#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 9/25 DPs: a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(x1) TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) Arctic Interpretation Processor: dimension: 2 interpretation: [a#](x0) = [0 0]x0, [-& 0 ] [0] [c](x0) = [0 1 ]x0 + [0], [1 1] [0] [b](x0) = [0 0]x0 + [2], [1 0] [0] [a](x0) = [0 0]x0 + [0] orientation: a#(b(x1)) = [1 1]x1 + [2] >= [1 1]x1 + [1] = a#(c(a(x1))) a#(b(x1)) = [1 1]x1 + [2] >= [0 0]x1 = a#(x1) [1 0] [0] a(x1) = [0 0]x1 + [0] >= x1 = x1 [2 2] [2] [2 2] [2] a(b(x1)) = [1 1]x1 + [2] >= [1 1]x1 + [2] = b(a(c(a(x1)))) [1 1] [0] b(x1) = [0 0]x1 + [2] >= x1 = x1 [1 2] [1] [1 1] [0] c(c(c(x1))) = [2 3]x1 + [2] >= [0 0]x1 + [2] = b(x1) problem: DPs: a#(b(x1)) -> a#(c(a(x1))) TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) EDG Processor: DPs: a#(b(x1)) -> a#(c(a(x1))) TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) graph: a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> a#(c(a(x1))) Arctic Interpretation Processor: dimension: 2 interpretation: [a#](x0) = [0 -&]x0 + [0], [-& 0 ] [0] [c](x0) = [0 1 ]x0 + [1], [1 1 ] [2] [b](x0) = [-& 0 ]x0 + [3], [1 0] [-&] [a](x0) = [0 0]x0 + [1 ] orientation: a#(b(x1)) = [1 1]x1 + [2] >= [0 0]x1 + [1] = a#(c(a(x1))) [1 0] [-&] a(x1) = [0 0]x1 + [1 ] >= x1 = x1 [2 2] [3] [2 2] [3] a(b(x1)) = [1 1]x1 + [3] >= [1 1]x1 + [3] = b(a(c(a(x1)))) [1 1 ] [2] b(x1) = [-& 0 ]x1 + [3] >= x1 = x1 [1 2] [2] [1 1 ] [2] c(c(c(x1))) = [2 3]x1 + [3] >= [-& 0 ]x1 + [3] = b(x1) problem: DPs: TRS: a(x1) -> x1 a(b(x1)) -> b(a(c(a(x1)))) b(x1) -> x1 c(c(c(x1))) -> b(x1) Qed