YES Problem: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 Proof: DP Processor: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) b#(b(c(x1))) -> a#(x1) b#(b(c(x1))) -> c#(a(x1)) b#(b(c(x1))) -> b#(c(a(x1))) b#(b(c(x1))) -> c#(b(c(a(x1)))) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 TDG Processor: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) b#(b(c(x1))) -> a#(x1) b#(b(c(x1))) -> c#(a(x1)) b#(b(c(x1))) -> b#(c(a(x1))) b#(b(c(x1))) -> c#(b(c(a(x1)))) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 graph: b#(b(c(x1))) -> b#(c(a(x1))) -> b#(b(c(x1))) -> c#(b(c(a(x1)))) b#(b(c(x1))) -> b#(c(a(x1))) -> b#(b(c(x1))) -> b#(c(a(x1))) b#(b(c(x1))) -> b#(c(a(x1))) -> b#(b(c(x1))) -> c#(a(x1)) b#(b(c(x1))) -> b#(c(a(x1))) -> b#(b(c(x1))) -> a#(x1) b#(b(c(x1))) -> a#(x1) -> a#(x1) -> b#(b(x1)) b#(b(c(x1))) -> a#(x1) -> a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) -> b#(b(c(x1))) -> c#(b(c(a(x1)))) a#(x1) -> b#(b(x1)) -> b#(b(c(x1))) -> b#(c(a(x1))) a#(x1) -> b#(b(x1)) -> b#(b(c(x1))) -> c#(a(x1)) a#(x1) -> b#(b(x1)) -> b#(b(c(x1))) -> a#(x1) a#(x1) -> b#(x1) -> b#(b(c(x1))) -> c#(b(c(a(x1)))) a#(x1) -> b#(x1) -> b#(b(c(x1))) -> b#(c(a(x1))) a#(x1) -> b#(x1) -> b#(b(c(x1))) -> c#(a(x1)) a#(x1) -> b#(x1) -> b#(b(c(x1))) -> a#(x1) SCC Processor: #sccs: 1 #rules: 4 #arcs: 14/36 DPs: b#(b(c(x1))) -> b#(c(a(x1))) b#(b(c(x1))) -> a#(x1) a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 interpretation: [b#](x0) = [1 0]x0 + [0], [a#](x0) = [1 3]x0 + [2], [-& 0 ] [1] [c](x0) = [0 2 ]x0 + [3], [-& 0 ] [0] [b](x0) = [0 -&]x0 + [0], [0 0 ] [0] [a](x0) = [-& 0 ]x0 + [0] orientation: b#(b(c(x1))) = [1 3]x1 + [4] >= [0 2]x1 + [3] = b#(c(a(x1))) b#(b(c(x1))) = [1 3]x1 + [4] >= [1 3]x1 + [2] = a#(x1) a#(x1) = [1 3]x1 + [2] >= [1 0]x1 + [0] = b#(x1) a#(x1) = [1 3]x1 + [2] >= [0 1]x1 + [1] = b#(b(x1)) [0 0 ] [0] [0] a(x1) = [-& 0 ]x1 + [0] >= x1 + [0] = b(b(x1)) [-& 0 ] [1] [-& 0 ] [1] b(b(c(x1))) = [0 2 ]x1 + [3] >= [0 2 ]x1 + [3] = c(b(c(a(x1)))) [0 2] [3] c(c(x1)) = [2 4]x1 + [5] >= x1 = x1 problem: DPs: b#(b(c(x1))) -> a#(x1) a#(x1) -> b#(x1) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 EDG Processor: DPs: b#(b(c(x1))) -> a#(x1) a#(x1) -> b#(x1) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 graph: b#(b(c(x1))) -> a#(x1) -> a#(x1) -> b#(x1) a#(x1) -> b#(x1) -> b#(b(c(x1))) -> a#(x1) CDG Processor: DPs: b#(b(c(x1))) -> a#(x1) a#(x1) -> b#(x1) TRS: a(x1) -> b(b(x1)) b(b(c(x1))) -> c(b(c(a(x1)))) c(c(x1)) -> x1 graph: b#(b(c(x1))) -> a#(x1) -> a#(x1) -> b#(x1) SCC Processor: #sccs: 0 #rules: 0 #arcs: 1/4