YES

Problem:
 c(b(a(a(x1)))) -> a(a(b(a(a(b(c(b(a(c(x1))))))))))

Proof:
 DP Processor:
  DPs:
   c#(b(a(a(x1)))) -> c#(x1)
   c#(b(a(a(x1)))) -> c#(b(a(c(x1))))
  TRS:
   c(b(a(a(x1)))) -> a(a(b(a(a(b(c(b(a(c(x1))))))))))
  Matrix Interpretation Processor: dim=4
   
   interpretation:
    [c#](x0) = [0 1 0 1]x0,
    
              [0 0 0 0]  
              [0 1 0 1]  
    [c](x0) = [0 1 0 0]x0
              [0 1 0 1]  ,
    
              [0 0 0 0]  
              [0 1 0 0]  
    [b](x0) = [0 0 0 0]x0
              [0 0 0 1]  ,
    
              [0 1 0 0]     [0]
              [0 0 1 0]     [0]
    [a](x0) = [0 0 0 1]x0 + [1]
              [1 0 0 0]     [0]
   orientation:
    c#(b(a(a(x1)))) = [0 1 0 1]x1 + [1] >= [0 1 0 1]x1 = c#(x1)
    
    c#(b(a(a(x1)))) = [0 1 0 1]x1 + [1] >= [0 1 0 0]x1 = c#(b(a(c(x1))))
    
                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                                   
                     [0 1 0 1]     [1]    [0 1 0 0]     [1]                                   
    c(b(a(a(x1)))) = [0 0 0 1]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(b(a(a(b(c(b(a(c(x1))))))))))
                     [0 1 0 1]     [1]    [0 1 0 0]     [1]                                   
   problem:
    DPs:
     
    TRS:
     c(b(a(a(x1)))) -> a(a(b(a(a(b(c(b(a(c(x1))))))))))
   Qed