YES Problem: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) Proof: DP Processor: DPs: b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) b#(a(a(b(a(b(x1)))))) -> b#(b(a(x1))) b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) CDG Processor: DPs: b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) b#(a(a(b(a(b(x1)))))) -> b#(b(a(x1))) b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) graph: b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) -> b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) -> b#(a(a(b(a(b(x1)))))) -> b#(b(a(x1))) b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) -> b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) -> b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) -> b#(a(a(b(a(b(x1)))))) -> b#(b(a(x1))) b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) -> b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) SCC Processor: #sccs: 1 #rules: 2 #arcs: 6/9 DPs: b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) b#(a(a(b(a(b(x1)))))) -> b#(a(x1)) TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) Arctic Interpretation Processor: dimension: 1 interpretation: [b#](x0) = x0, [a](x0) = x0, [b](x0) = 1x0 orientation: b#(a(a(b(a(b(x1)))))) = 2x1 >= 2x1 = b#(a(a(b(b(a(x1)))))) b#(a(a(b(a(b(x1)))))) = 2x1 >= x1 = b#(a(x1)) b(a(a(b(a(b(x1)))))) = 3x1 >= 3x1 = a(b(a(a(b(b(a(x1))))))) problem: DPs: b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) EDG Processor: DPs: b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) graph: b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) -> b#(a(a(b(a(b(x1)))))) -> b#(a(a(b(b(a(x1)))))) Matrix Interpretation Processor: dim=4 interpretation: [b#](x0) = [1 0 0 0]x0, [0 1 0 0] [1 0 0 0] [a](x0) = [0 0 0 1]x0 [0 0 0 0] , [0 0 1 0] [0] [0 0 0 0] [0] [b](x0) = [1 0 0 1]x0 + [0] [0 1 0 0] [1] orientation: b#(a(a(b(a(b(x1)))))) = [0 1 0 0]x1 + [1] >= [0 1 0 0]x1 = b#(a(a(b(b(a(x1)))))) [0 0 0 0] [0] [0] [0 0 0 0] [0] [0] b(a(a(b(a(b(x1)))))) = [0 1 0 0]x1 + [1] >= [1] = a(b(a(a(b(b(a(x1))))))) [0 0 0 0] [1] [0] problem: DPs: TRS: b(a(a(b(a(b(x1)))))) -> a(b(a(a(b(b(a(x1))))))) Qed