YES

Problem:
 app(nil(),y) -> y
 app(add(n,x),y) -> add(n,app(x,y))
 reverse(nil()) -> nil()
 reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
 shuffle(nil()) -> nil()
 shuffle(add(n,x)) -> add(n,shuffle(reverse(x)))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [shuffle](x0) = 2x0 + 4,
   
   [reverse](x0) = x0,
   
   [add](x0, x1) = 2x0 + x1,
   
   [app](x0, x1) = x0 + x1,
   
   [nil] = 0
  orientation:
   app(nil(),y) = y >= y = y
   
   app(add(n,x),y) = 2n + x + y >= 2n + x + y = add(n,app(x,y))
   
   reverse(nil()) = 0 >= 0 = nil()
   
   reverse(add(n,x)) = 2n + x >= 2n + x = app(reverse(x),add(n,nil()))
   
   shuffle(nil()) = 4 >= 0 = nil()
   
   shuffle(add(n,x)) = 4n + 2x + 4 >= 2n + 2x + 4 = add(n,shuffle(reverse(x)))
  problem:
   app(nil(),y) -> y
   app(add(n,x),y) -> add(n,app(x,y))
   reverse(nil()) -> nil()
   reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
   shuffle(add(n,x)) -> add(n,shuffle(reverse(x)))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [shuffle](x0) = 2x0,
    
    [reverse](x0) = x0,
    
    [add](x0, x1) = 4x0 + x1 + 2,
    
    [app](x0, x1) = x0 + x1,
    
    [nil] = 0
   orientation:
    app(nil(),y) = y >= y = y
    
    app(add(n,x),y) = 4n + x + y + 2 >= 4n + x + y + 2 = add(n,app(x,y))
    
    reverse(nil()) = 0 >= 0 = nil()
    
    reverse(add(n,x)) = 4n + x + 2 >= 4n + x + 2 = app(reverse(x),add(n,nil()))
    
    shuffle(add(n,x)) = 8n + 2x + 4 >= 4n + 2x + 2 = add(n,shuffle(reverse(x)))
   problem:
    app(nil(),y) -> y
    app(add(n,x),y) -> add(n,app(x,y))
    reverse(nil()) -> nil()
    reverse(add(n,x)) -> app(reverse(x),add(n,nil()))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [reverse](x0) = 5x0 + 2,
     
     [add](x0, x1) = 4x0 + x1 + 3,
     
     [app](x0, x1) = x0 + x1 + 7,
     
     [nil] = 0
    orientation:
     app(nil(),y) = y + 7 >= y = y
     
     app(add(n,x),y) = 4n + x + y + 10 >= 4n + x + y + 10 = add(n,app(x,y))
     
     reverse(nil()) = 2 >= 0 = nil()
     
     reverse(add(n,x)) = 20n + 5x + 17 >= 4n + 5x + 12 = app(reverse(x),add(n,nil()))
    problem:
     app(add(n,x),y) -> add(n,app(x,y))
    Matrix Interpretation Processor: dim=1
     
     interpretation:
      [add](x0, x1) = 5x0 + x1 + 1,
      
      [app](x0, x1) = 5x0 + x1 + 1
     orientation:
      app(add(n,x),y) = 25n + 5x + y + 6 >= 5n + 5x + y + 2 = add(n,app(x,y))
     problem:
      
     Qed