YES

Problem:
 div(0(),y) -> 0()
 div(x,y) -> quot(x,y,y)
 quot(0(),s(y),z) -> 0()
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0(),s(z)) -> s(div(x,s(z)))

Proof:
 DP Processor:
  DPs:
   div#(x,y) -> quot#(x,y,y)
   quot#(s(x),s(y),z) -> quot#(x,y,z)
   quot#(x,0(),s(z)) -> div#(x,s(z))
  TRS:
   div(0(),y) -> 0()
   div(x,y) -> quot(x,y,y)
   quot(0(),s(y),z) -> 0()
   quot(s(x),s(y),z) -> quot(x,y,z)
   quot(x,0(),s(z)) -> s(div(x,s(z)))
  TDG Processor:
   DPs:
    div#(x,y) -> quot#(x,y,y)
    quot#(s(x),s(y),z) -> quot#(x,y,z)
    quot#(x,0(),s(z)) -> div#(x,s(z))
   TRS:
    div(0(),y) -> 0()
    div(x,y) -> quot(x,y,y)
    quot(0(),s(y),z) -> 0()
    quot(s(x),s(y),z) -> quot(x,y,z)
    quot(x,0(),s(z)) -> s(div(x,s(z)))
   graph:
    quot#(s(x),s(y),z) -> quot#(x,y,z) ->
    quot#(x,0(),s(z)) -> div#(x,s(z))
    quot#(s(x),s(y),z) -> quot#(x,y,z) ->
    quot#(s(x),s(y),z) -> quot#(x,y,z)
    quot#(x,0(),s(z)) -> div#(x,s(z)) -> div#(x,y) -> quot#(x,y,y)
    div#(x,y) -> quot#(x,y,y) -> quot#(x,0(),s(z)) -> div#(x,s(z))
    div#(x,y) -> quot#(x,y,y) -> quot#(s(x),s(y),z) -> quot#(x,y,z)
   Subterm Criterion Processor:
    simple projection:
     pi(div#) = 0
     pi(quot#) = 0
    problem:
     DPs:
      div#(x,y) -> quot#(x,y,y)
      quot#(x,0(),s(z)) -> div#(x,s(z))
     TRS:
      div(0(),y) -> 0()
      div(x,y) -> quot(x,y,y)
      quot(0(),s(y),z) -> 0()
      quot(s(x),s(y),z) -> quot(x,y,z)
      quot(x,0(),s(z)) -> s(div(x,s(z)))
    EDG Processor:
     DPs:
      div#(x,y) -> quot#(x,y,y)
      quot#(x,0(),s(z)) -> div#(x,s(z))
     TRS:
      div(0(),y) -> 0()
      div(x,y) -> quot(x,y,y)
      quot(0(),s(y),z) -> 0()
      quot(s(x),s(y),z) -> quot(x,y,z)
      quot(x,0(),s(z)) -> s(div(x,s(z)))
     graph:
      quot#(x,0(),s(z)) -> div#(x,s(z)) -> div#(x,y) -> quot#(x,y,y)
      div#(x,y) -> quot#(x,y,y) -> quot#(x,0(),s(z)) -> div#(x,s(z))
     KBO Processor:
      argument filtering:
       pi(0) = []
       pi(div) = [0,1]
       pi(quot) = [2]
       pi(s) = []
       pi(div#) = 1
       pi(quot#) = 1
      weight function:
       w0 = 1
       w(s) = w(quot) = w(div) = w(0) = 1
       w(quot#) = w(div#) = 0
      precedence:
       0 > quot# ~ div# ~ s ~ quot ~ div
      problem:
       DPs:
        div#(x,y) -> quot#(x,y,y)
       TRS:
        div(0(),y) -> 0()
        div(x,y) -> quot(x,y,y)
        quot(0(),s(y),z) -> 0()
        quot(s(x),s(y),z) -> quot(x,y,z)
        quot(x,0(),s(z)) -> s(div(x,s(z)))
      SCC Processor:
       #sccs: 0
       #rules: 0
       #arcs: 2/1