YES

Problem:
 f(s(x),y) -> f(x,s(x))
 f(x,s(y)) -> f(y,x)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0, x1) = 2x0 + x1,
   
   [s](x0) = 2x0 + 4
  orientation:
   f(s(x),y) = 4x + y + 8 >= 4x + 4 = f(x,s(x))
   
   f(x,s(y)) = 2x + 2y + 4 >= x + 2y = f(y,x)
  problem:
   
  Qed