YES Problem: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Proof: DP Processor: DPs: le#(s(X),s(Y)) -> le#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) TDG Processor: DPs: le#(s(X),s(Y)) -> le#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) graph: quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) -> quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) -> quot#(s(X),s(Y)) -> minus#(X,Y) quot#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) quot#(s(X),s(Y)) -> minus#(X,Y) -> minus#(s(X),Y) -> le#(s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) -> minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) -> minus#(s(X),Y) -> le#(s(X),Y) minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) -> ifMinus#(false(),s(X),Y) -> minus#(X,Y) minus#(s(X),Y) -> le#(s(X),Y) -> le#(s(X),s(Y)) -> le#(X,Y) le#(s(X),s(Y)) -> le#(X,Y) -> le#(s(X),s(Y)) -> le#(X,Y) SCC Processor: #sccs: 3 #rules: 4 #arcs: 9/36 DPs: quot#(s(X),s(Y)) -> quot#(minus(X,Y),s(Y)) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Arctic Interpretation Processor: dimension: 1 interpretation: [quot#](x0, x1) = 4x0 + 0, [quot](x0, x1) = 3x0, [ifMinus](x0, x1, x2) = x0 + x1 + 0, [minus](x0, x1) = x0, [false] = 0, [s](x0) = 1x0 + 0, [true] = 4, [le](x0, x1) = x0 + 0, [0] = 4 orientation: quot#(s(X),s(Y)) = 5X + 4 >= 4X + 0 = quot#(minus(X,Y),s(Y)) le(0(),Y) = 4 >= 4 = true() le(s(X),0()) = 1X + 0 >= 0 = false() le(s(X),s(Y)) = 1X + 0 >= X + 0 = le(X,Y) minus(0(),Y) = 4 >= 4 = 0() minus(s(X),Y) = 1X + 0 >= 1X + 0 = ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) = 1X + 4 >= 4 = 0() ifMinus(false(),s(X),Y) = 1X + 0 >= 1X + 0 = s(minus(X,Y)) quot(0(),s(Y)) = 7 >= 4 = 0() quot(s(X),s(Y)) = 4X + 3 >= 4X + 0 = s(quot(minus(X,Y),s(Y))) problem: DPs: TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Qed DPs: minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) ifMinus#(false(),s(X),Y) -> minus#(X,Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(minus#) = 0 pi(ifMinus#) = 1 problem: DPs: minus#(s(X),Y) -> ifMinus#(le(s(X),Y),s(X),Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) SCC Processor: #sccs: 0 #rules: 0 #arcs: 2/1 DPs: le#(s(X),s(Y)) -> le#(X,Y) TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Subterm Criterion Processor: simple projection: pi(le#) = 1 problem: DPs: TRS: le(0(),Y) -> true() le(s(X),0()) -> false() le(s(X),s(Y)) -> le(X,Y) minus(0(),Y) -> 0() minus(s(X),Y) -> ifMinus(le(s(X),Y),s(X),Y) ifMinus(true(),s(X),Y) -> 0() ifMinus(false(),s(X),Y) -> s(minus(X,Y)) quot(0(),s(Y)) -> 0() quot(s(X),s(Y)) -> s(quot(minus(X,Y),s(Y))) Qed