YES

Problem:
 minus(minus(x)) -> x
 minus(h(x)) -> h(minus(x))
 minus(f(x,y)) -> f(minus(y),minus(x))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0, x1) = 2x0 + 2x1 + 1,
   
   [h](x0) = 4x0 + 2,
   
   [minus](x0) = 4x0 + 1
  orientation:
   minus(minus(x)) = 16x + 5 >= x = x
   
   minus(h(x)) = 16x + 9 >= 16x + 6 = h(minus(x))
   
   minus(f(x,y)) = 8x + 8y + 5 >= 8x + 8y + 5 = f(minus(y),minus(x))
  problem:
   minus(f(x,y)) -> f(minus(y),minus(x))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [f](x0, x1) = 4x0 + 4x1 + 2,
    
    [minus](x0) = 5x0 + 1
   orientation:
    minus(f(x,y)) = 20x + 20y + 11 >= 20x + 20y + 10 = f(minus(y),minus(x))
   problem:
    
   Qed