YES

Problem:
 rev(nil()) -> nil()
 rev(.(x,y)) -> ++(rev(y),.(x,nil()))
 car(.(x,y)) -> x
 cdr(.(x,y)) -> y
 null(nil()) -> true()
 null(.(x,y)) -> false()
 ++(nil(),y) -> y
 ++(.(x,y),z) -> .(x,++(y,z))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [false] = 0,
   
   [true] = 4,
   
   [null](x0) = x0 + 4,
   
   [cdr](x0) = 5x0 + 1,
   
   [car](x0) = 6x0,
   
   [++](x0, x1) = x0 + x1,
   
   [.](x0, x1) = 2x0 + x1 + 3,
   
   [rev](x0) = 2x0,
   
   [nil] = 0
  orientation:
   rev(nil()) = 0 >= 0 = nil()
   
   rev(.(x,y)) = 4x + 2y + 6 >= 2x + 2y + 3 = ++(rev(y),.(x,nil()))
   
   car(.(x,y)) = 12x + 6y + 18 >= x = x
   
   cdr(.(x,y)) = 10x + 5y + 16 >= y = y
   
   null(nil()) = 4 >= 4 = true()
   
   null(.(x,y)) = 2x + y + 7 >= 0 = false()
   
   ++(nil(),y) = y >= y = y
   
   ++(.(x,y),z) = 2x + y + z + 3 >= 2x + y + z + 3 = .(x,++(y,z))
  problem:
   rev(nil()) -> nil()
   null(nil()) -> true()
   ++(nil(),y) -> y
   ++(.(x,y),z) -> .(x,++(y,z))
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [true] = 0,
    
    [null](x0) = x0,
    
    [++](x0, x1) = x0 + x1 + 3,
    
    [.](x0, x1) = x0 + x1 + 4,
    
    [rev](x0) = x0,
    
    [nil] = 0
   orientation:
    rev(nil()) = 0 >= 0 = nil()
    
    null(nil()) = 0 >= 0 = true()
    
    ++(nil(),y) = y + 3 >= y = y
    
    ++(.(x,y),z) = x + y + z + 7 >= x + y + z + 7 = .(x,++(y,z))
   problem:
    rev(nil()) -> nil()
    null(nil()) -> true()
    ++(.(x,y),z) -> .(x,++(y,z))
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [true] = 0,
     
     [null](x0) = x0 + 3,
     
     [++](x0, x1) = 2x0 + x1 + 6,
     
     [.](x0, x1) = 4x0 + x1 + 2,
     
     [rev](x0) = 4x0,
     
     [nil] = 1
    orientation:
     rev(nil()) = 4 >= 1 = nil()
     
     null(nil()) = 4 >= 0 = true()
     
     ++(.(x,y),z) = 8x + 2y + z + 10 >= 4x + 2y + z + 8 = .(x,++(y,z))
    problem:
     
    Qed