YES Problem: norm(nil()) -> 0() norm(g(x,y)) -> s(norm(x)) f(x,nil()) -> g(nil(),x) f(x,g(y,z)) -> g(f(x,y),z) rem(nil(),y) -> nil() rem(g(x,y),0()) -> g(x,y) rem(g(x,y),s(z)) -> rem(x,z) Proof: Matrix Interpretation Processor: dim=1 interpretation: [rem](x0, x1) = 2x0 + x1 + 4, [f](x0, x1) = x0 + 5x1, [s](x0) = x0, [g](x0, x1) = x0 + x1, [0] = 0, [norm](x0) = x0, [nil] = 4 orientation: norm(nil()) = 4 >= 0 = 0() norm(g(x,y)) = x + y >= x = s(norm(x)) f(x,nil()) = x + 20 >= x + 4 = g(nil(),x) f(x,g(y,z)) = x + 5y + 5z >= x + 5y + z = g(f(x,y),z) rem(nil(),y) = y + 12 >= 4 = nil() rem(g(x,y),0()) = 2x + 2y + 4 >= x + y = g(x,y) rem(g(x,y),s(z)) = 2x + 2y + z + 4 >= 2x + z + 4 = rem(x,z) problem: norm(g(x,y)) -> s(norm(x)) f(x,g(y,z)) -> g(f(x,y),z) rem(g(x,y),s(z)) -> rem(x,z) Matrix Interpretation Processor: dim=1 interpretation: [rem](x0, x1) = 7x0 + 3x1 + 2, [f](x0, x1) = x0 + x1 + 1, [s](x0) = x0 + 2, [g](x0, x1) = x0 + x1 + 2, [norm](x0) = x0 + 4 orientation: norm(g(x,y)) = x + y + 6 >= x + 6 = s(norm(x)) f(x,g(y,z)) = x + y + z + 3 >= x + y + z + 3 = g(f(x,y),z) rem(g(x,y),s(z)) = 7x + 7y + 3z + 22 >= 7x + 3z + 2 = rem(x,z) problem: norm(g(x,y)) -> s(norm(x)) f(x,g(y,z)) -> g(f(x,y),z) Matrix Interpretation Processor: dim=1 interpretation: [f](x0, x1) = x0 + 2x1 + 5, [s](x0) = x0 + 1, [g](x0, x1) = x0 + 5x1 + 1, [norm](x0) = x0 + 5 orientation: norm(g(x,y)) = x + 5y + 6 >= x + 6 = s(norm(x)) f(x,g(y,z)) = x + 2y + 10z + 7 >= x + 2y + 5z + 6 = g(f(x,y),z) problem: norm(g(x,y)) -> s(norm(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [s](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [1 0 0] [1] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0], [1 0 0] [norm](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 0] [1 0 0] [1] [1 0 0] norm(g(x,y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x = s(norm(x)) [0 0 0] [0 0 0] [0] [0 0 0] problem: Qed