YES

Problem:
 f(g(h(x,y)),f(a(),a())) -> f(h(x,x),g(f(y,a())))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [f](x0, x1) = x0 + x1,
   
   [a] = 0,
   
   [g](x0) = 2x0 + 1,
   
   [h](x0, x1) = x0 + x1 + 1
  orientation:
   f(g(h(x,y)),f(a(),a())) = 2x + 2y + 3 >= 2x + 2y + 2 = f(h(x,x),g(f(y,a())))
  problem:
   
  Qed