YES Problem: c(c(x1)) -> a(b(x1)) b(x1) -> a(a(x1)) b(b(b(x1))) -> a(c(b(x1))) a(c(a(x1))) -> a(c(c(x1))) Proof: Arctic Interpretation Processor: dimension: 2 interpretation: [0 3 ] [a](x0) = [-& 0 ]x0, [2 3] [b](x0) = [0 0]x0, [0 3] [c](x0) = [0 0]x0 orientation: [3 3] [3 3] c(c(x1)) = [0 3]x1 >= [0 0]x1 = a(b(x1)) [2 3] [0 3 ] b(x1) = [0 0]x1 >= [-& 0 ]x1 = a(a(x1)) [6 7] [5 6] b(b(b(x1))) = [4 5]x1 >= [2 3]x1 = a(c(b(x1))) [3 6] [3 6] a(c(a(x1))) = [0 3]x1 >= [0 3]x1 = a(c(c(x1))) problem: c(c(x1)) -> a(b(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> a(c(c(x1))) String Reversal Processor: c(c(x1)) -> b(a(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> c(c(a(x1))) DP Processor: DPs: c#(c(x1)) -> a#(x1) c#(c(x1)) -> b#(a(x1)) b#(x1) -> a#(x1) b#(x1) -> a#(a(x1)) a#(c(a(x1))) -> c#(c(a(x1))) TRS: c(c(x1)) -> b(a(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> c(c(a(x1))) TDG Processor: DPs: c#(c(x1)) -> a#(x1) c#(c(x1)) -> b#(a(x1)) b#(x1) -> a#(x1) b#(x1) -> a#(a(x1)) a#(c(a(x1))) -> c#(c(a(x1))) TRS: c(c(x1)) -> b(a(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> c(c(a(x1))) graph: b#(x1) -> a#(a(x1)) -> a#(c(a(x1))) -> c#(c(a(x1))) b#(x1) -> a#(x1) -> a#(c(a(x1))) -> c#(c(a(x1))) a#(c(a(x1))) -> c#(c(a(x1))) -> c#(c(x1)) -> b#(a(x1)) a#(c(a(x1))) -> c#(c(a(x1))) -> c#(c(x1)) -> a#(x1) c#(c(x1)) -> b#(a(x1)) -> b#(x1) -> a#(a(x1)) c#(c(x1)) -> b#(a(x1)) -> b#(x1) -> a#(x1) c#(c(x1)) -> a#(x1) -> a#(c(a(x1))) -> c#(c(a(x1))) Arctic Interpretation Processor: dimension: 2 interpretation: [b#](x0) = [1 -&]x0 + [0], [a#](x0) = [1 -&]x0 + [0], [c#](x0) = [-& 0 ]x0 + [0], [0 -&] [-4] [a](x0) = [1 -4]x0 + [1 ], [0 1] [0] [b](x0) = [1 0]x0 + [1], [0 3 ] [-&] [c](x0) = [1 -&]x0 + [1 ] orientation: c#(c(x1)) = [1 -&]x1 + [1] >= [1 -&]x1 + [0] = a#(x1) c#(c(x1)) = [1 -&]x1 + [1] >= [1 -&]x1 + [0] = b#(a(x1)) b#(x1) = [1 -&]x1 + [0] >= [1 -&]x1 + [0] = a#(x1) b#(x1) = [1 -&]x1 + [0] >= [1 -&]x1 + [0] = a#(a(x1)) a#(c(a(x1))) = [5 0]x1 + [5] >= [1 -&]x1 + [1] = c#(c(a(x1))) [4 3] [4] [2 -3] [2] c(c(x1)) = [1 4]x1 + [1] >= [1 -4]x1 + [1] = b(a(x1)) [0 1] [0] [0 -&] [-4] b(x1) = [1 0]x1 + [1] >= [1 -8]x1 + [1 ] = a(a(x1)) [4 -1] [4] [4 -1] [4] a(c(a(x1))) = [5 0 ]x1 + [5] >= [5 0 ]x1 + [5] = c(c(a(x1))) problem: DPs: c#(c(x1)) -> a#(x1) c#(c(x1)) -> b#(a(x1)) b#(x1) -> a#(x1) b#(x1) -> a#(a(x1)) TRS: c(c(x1)) -> b(a(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> c(c(a(x1))) EDG Processor: DPs: c#(c(x1)) -> a#(x1) c#(c(x1)) -> b#(a(x1)) b#(x1) -> a#(x1) b#(x1) -> a#(a(x1)) TRS: c(c(x1)) -> b(a(x1)) b(x1) -> a(a(x1)) a(c(a(x1))) -> c(c(a(x1))) graph: c#(c(x1)) -> b#(a(x1)) -> b#(x1) -> a#(x1) c#(c(x1)) -> b#(a(x1)) -> b#(x1) -> a#(a(x1)) SCC Processor: #sccs: 0 #rules: 0 #arcs: 2/16