YES

Problem:
 t(o(x1)) -> m(a(x1))
 t(e(x1)) -> n(s(x1))
 a(l(x1)) -> a(t(x1))
 o(m(a(x1))) -> t(e(n(x1)))
 s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
 n(s(x1)) -> a(l(a(t(x1))))

Proof:
 String Reversal Processor:
  o(t(x1)) -> a(m(x1))
  e(t(x1)) -> s(n(x1))
  l(a(x1)) -> t(a(x1))
  a(m(o(x1))) -> n(e(t(x1)))
  a(s(x1)) -> e(t(a(m(o(t(a(l(x1))))))))
  s(n(x1)) -> t(a(l(a(x1))))
  Matrix Interpretation Processor: dim=3
   
   interpretation:
              [1 1 0]     [0]
    [l](x0) = [0 0 0]x0 + [0]
              [1 1 0]     [1],
    
              [1 1 0]  
    [n](x0) = [0 0 0]x0
              [0 1 0]  ,
    
              [1 1 1]     [0]
    [s](x0) = [0 0 0]x0 + [1]
              [0 0 0]     [0],
    
              [1 0 1]     [0]
    [e](x0) = [0 0 0]x0 + [1]
              [0 0 0]     [0],
    
              [1 0 0]     [0]
    [m](x0) = [0 1 0]x0 + [0]
              [1 0 0]     [1],
    
              [1 1 0]  
    [a](x0) = [0 1 0]x0
              [0 0 1]  ,
    
              [1 1 0]  
    [t](x0) = [0 0 0]x0
              [0 1 0]  ,
    
              [1 1 0]     [1]
    [o](x0) = [0 1 1]x0 + [0]
              [1 0 0]     [1]
   orientation:
               [1 1 0]     [1]    [1 1 0]     [0]           
    o(t(x1)) = [0 1 0]x1 + [0] >= [0 1 0]x1 + [0] = a(m(x1))
               [1 1 0]     [1]    [1 0 0]     [1]           
    
               [1 2 0]     [0]    [1 2 0]     [0]           
    e(t(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = s(n(x1))
               [0 0 0]     [0]    [0 0 0]     [0]           
    
               [1 2 0]     [0]    [1 2 0]             
    l(a(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 = t(a(x1))
               [1 2 0]     [1]    [0 1 0]             
    
                  [1 2 1]     [1]    [1 2 0]     [1]              
    a(m(o(x1))) = [0 1 1]x1 + [0] >= [0 0 0]x1 + [0] = n(e(t(x1)))
                  [1 1 0]     [2]    [0 0 0]     [1]              
    
               [1 1 1]     [1]    [1 1 0]     [1]                             
    a(s(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = e(t(a(m(o(t(a(l(x1))))))))
               [0 0 0]     [0]    [0 0 0]     [0]                             
    
               [1 2 0]     [0]    [1 2 0]                   
    s(n(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = t(a(l(a(x1))))
               [0 0 0]     [0]    [0 0 0]                   
   problem:
    e(t(x1)) -> s(n(x1))
    l(a(x1)) -> t(a(x1))
    a(m(o(x1))) -> n(e(t(x1)))
    a(s(x1)) -> e(t(a(m(o(t(a(l(x1))))))))
    s(n(x1)) -> t(a(l(a(x1))))
   String Reversal Processor:
    t(e(x1)) -> n(s(x1))
    a(l(x1)) -> a(t(x1))
    o(m(a(x1))) -> t(e(n(x1)))
    s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
    n(s(x1)) -> a(l(a(t(x1))))
    Matrix Interpretation Processor: dim=3
     
     interpretation:
                [1 0 0]  
      [l](x0) = [0 0 1]x0
                [0 0 0]  ,
      
                [1 0 0]  
      [n](x0) = [0 0 1]x0
                [0 0 0]  ,
      
                [1 1 0]     [1]
      [s](x0) = [1 0 0]x0 + [0]
                [0 0 0]     [1],
      
                [1 1 0]     [1]
      [e](x0) = [0 0 0]x0 + [0]
                [1 0 0]     [1],
      
                [1 0 0]     [1]
      [m](x0) = [0 0 0]x0 + [0]
                [0 0 0]     [1],
      
                [1 0 1]     [0]
      [a](x0) = [0 1 0]x0 + [1]
                [0 0 0]     [0],
      
                [1 0 0]  
      [t](x0) = [0 0 1]x0
                [0 0 0]  ,
      
                [1 0 0]     [0]
      [o](x0) = [1 0 0]x0 + [0]
                [0 0 1]     [1]
     orientation:
                 [1 1 0]     [1]    [1 1 0]     [1]           
      t(e(x1)) = [1 0 0]x1 + [1] >= [0 0 0]x1 + [1] = n(s(x1))
                 [0 0 0]     [0]    [0 0 0]     [0]           
      
                 [1 0 0]     [0]    [1 0 0]     [0]           
      a(l(x1)) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = a(t(x1))
                 [0 0 0]     [0]    [0 0 0]     [0]           
      
                    [1 0 1]     [1]    [1 0 1]     [1]              
      o(m(a(x1))) = [1 0 1]x1 + [1] >= [1 0 0]x1 + [1] = t(e(n(x1)))
                    [0 0 0]     [2]    [0 0 0]     [0]              
      
                 [1 1 1]     [2]    [1 1 0]     [2]                             
      s(a(x1)) = [1 0 1]x1 + [0] >= [0 0 0]x1 + [0] = l(a(t(o(m(a(t(e(x1))))))))
                 [0 0 0]     [1]    [0 0 0]     [0]                             
      
                 [1 1 0]     [1]    [1 0 0]     [0]                 
      n(s(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = a(l(a(t(x1))))
                 [0 0 0]     [0]    [0 0 0]     [0]                 
     problem:
      t(e(x1)) -> n(s(x1))
      a(l(x1)) -> a(t(x1))
      o(m(a(x1))) -> t(e(n(x1)))
      s(a(x1)) -> l(a(t(o(m(a(t(e(x1))))))))
     String Reversal Processor:
      e(t(x1)) -> s(n(x1))
      l(a(x1)) -> t(a(x1))
      a(m(o(x1))) -> n(e(t(x1)))
      a(s(x1)) -> e(t(a(m(o(t(a(l(x1))))))))
      Bounds Processor:
       bound: 4
       enrichment: match
       automaton:
        final states: {9}
        transitions:
         n3(97) -> 98*
         n3(94) -> 95*
         n3(106) -> 107*
         e1(34) -> 35*
         e1(24) -> 25*
         e3(105) -> 106*
         t1(17) -> 18*
         t1(29) -> 30*
         t1(33) -> 34*
         t1(23) -> 24*
         t3(104) -> 105*
         a1(32) -> 33*
         a1(16) -> 17*
         a1(28) -> 29*
         s3(95) -> 96*
         s3(98) -> 99*
         m1(31) -> 32*
         s4(134) -> 135*
         o1(30) -> 31*
         n4(133) -> 134*
         l1(27) -> 28*
         l1(73) -> 74*
         n1(25) -> 26*
         n1(43) -> 44*
         n1(13) -> 14*
         s1(14) -> 15*
         e2(70) -> 71*
         e2(88) -> 89*
         e0(9) -> 9*
         t2(87) -> 88*
         t2(69) -> 70*
         t2(83) -> 84*
         t0(9) -> 9*
         a2(82) -> 83*
         a2(86) -> 87*
         s0(9) -> 9*
         m2(85) -> 86*
         n0(9) -> 9*
         o2(84) -> 85*
         l0(9) -> 9*
         l2(136) -> 137*
         l2(81) -> 82*
         l2(108) -> 109*
         a0(9) -> 9*
         n2(40) -> 41*
         n2(49) -> 50*
         n2(71) -> 72*
         m0(9) -> 9*
         s2(50) -> 51*
         s2(41) -> 42*
         o0(9) -> 9*
         9 -> 27,23,16,13
         14 -> 81,73
         15 -> 9*
         17 -> 43*
         18 -> 28,9
         23 -> 40*
         26 -> 17,9
         30 -> 69*
         33 -> 49*
         35 -> 17,9
         42 -> 25*
         44 -> 14*
         50 -> 108*
         51 -> 35,9,23,13,16,27
         69 -> 97*
         72 -> 33*
         74 -> 28*
         84 -> 104*
         87 -> 94*
         89 -> 9,27,16,13,23,40,17
         95 -> 136*
         96 -> 89*
         99 -> 71*
         104 -> 133*
         107 -> 87*
         109 -> 82*
         135 -> 106*
         137 -> 82*
       problem:
        
       Qed