YES Problem: a(b(c(x1))) -> c(b(a(a(c(b(x1)))))) a(x1) -> x1 b(x1) -> x1 c(x1) -> x1 Proof: DP Processor: DPs: a#(b(c(x1))) -> b#(x1) a#(b(c(x1))) -> c#(b(x1)) a#(b(c(x1))) -> a#(c(b(x1))) a#(b(c(x1))) -> a#(a(c(b(x1)))) a#(b(c(x1))) -> b#(a(a(c(b(x1))))) a#(b(c(x1))) -> c#(b(a(a(c(b(x1)))))) TRS: a(b(c(x1))) -> c(b(a(a(c(b(x1)))))) a(x1) -> x1 b(x1) -> x1 c(x1) -> x1 TDG Processor: DPs: a#(b(c(x1))) -> b#(x1) a#(b(c(x1))) -> c#(b(x1)) a#(b(c(x1))) -> a#(c(b(x1))) a#(b(c(x1))) -> a#(a(c(b(x1)))) a#(b(c(x1))) -> b#(a(a(c(b(x1))))) a#(b(c(x1))) -> c#(b(a(a(c(b(x1)))))) TRS: a(b(c(x1))) -> c(b(a(a(c(b(x1)))))) a(x1) -> x1 b(x1) -> x1 c(x1) -> x1 graph: a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> c#(b(a(a(c(b(x1)))))) a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> b#(a(a(c(b(x1))))) a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> a#(a(c(b(x1)))) a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> a#(c(b(x1))) a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> c#(b(x1)) a#(b(c(x1))) -> a#(a(c(b(x1)))) -> a#(b(c(x1))) -> b#(x1) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> c#(b(a(a(c(b(x1)))))) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> b#(a(a(c(b(x1))))) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> a#(a(c(b(x1)))) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> a#(c(b(x1))) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> c#(b(x1)) a#(b(c(x1))) -> a#(c(b(x1))) -> a#(b(c(x1))) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 12/36 DPs: a#(b(c(x1))) -> a#(a(c(b(x1)))) a#(b(c(x1))) -> a#(c(b(x1))) TRS: a(b(c(x1))) -> c(b(a(a(c(b(x1)))))) a(x1) -> x1 b(x1) -> x1 c(x1) -> x1 Arctic Interpretation Processor: dimension: 2 interpretation: [a#](x0) = [2 0]x0 + [0], [0 -&] [0] [a](x0) = [1 0 ]x0 + [0], [0 0] [b](x0) = [0 0]x0, [0 0] [-&] [c](x0) = [1 1]x0 + [2 ] orientation: a#(b(c(x1))) = [3 3]x1 + [4] >= [2 2]x1 + [2] = a#(a(c(b(x1)))) a#(b(c(x1))) = [3 3]x1 + [4] >= [2 2]x1 + [2] = a#(c(b(x1))) [1 1] [2] [1 1] [2] a(b(c(x1))) = [2 2]x1 + [3] >= [2 2]x1 + [3] = c(b(a(a(c(b(x1)))))) [0 -&] [0] a(x1) = [1 0 ]x1 + [0] >= x1 = x1 [0 0] b(x1) = [0 0]x1 >= x1 = x1 [0 0] [-&] c(x1) = [1 1]x1 + [2 ] >= x1 = x1 problem: DPs: TRS: a(b(c(x1))) -> c(b(a(a(c(b(x1)))))) a(x1) -> x1 b(x1) -> x1 c(x1) -> x1 Qed