MAYBE

Problem:
 f(x,f(y,x)) -> f(f(x,x),f(a(),y))

Proof:
 DP Processor:
  DPs:
   f#(x,f(y,x)) -> f#(a(),y)
   f#(x,f(y,x)) -> f#(x,x)
   f#(x,f(y,x)) -> f#(f(x,x),f(a(),y))
  TRS:
   f(x,f(y,x)) -> f(f(x,x),f(a(),y))
  Arctic Interpretation Processor:
   dimension: 1
   interpretation:
    [f#](x0, x1) = -1x0 + 3x1 + 0,
    
    [a] = 0,
    
    [f](x0, x1) = 1x0 + 1x1 + 1
   orientation:
    f#(x,f(y,x)) = 4x + 4y + 4 >= 3y + 0 = f#(a(),y)
    
    f#(x,f(y,x)) = 4x + 4y + 4 >= 3x + 0 = f#(x,x)
    
    f#(x,f(y,x)) = 4x + 4y + 4 >= x + 4y + 4 = f#(f(x,x),f(a(),y))
    
    f(x,f(y,x)) = 2x + 2y + 2 >= 2x + 2y + 2 = f(f(x,x),f(a(),y))
   problem:
    DPs:
     f#(x,f(y,x)) -> f#(f(x,x),f(a(),y))
    TRS:
     f(x,f(y,x)) -> f(f(x,x),f(a(),y))
   Open