YES Problem: fst(0(),Z) -> nil() fst(s(X),cons(Y,Z)) -> cons(Y,n__fst(activate(X),activate(Z))) from(X) -> cons(X,n__from(s(X))) add(0(),X) -> X add(s(X),Y) -> s(n__add(activate(X),Y)) len(nil()) -> 0() len(cons(X,Z)) -> s(n__len(activate(Z))) fst(X1,X2) -> n__fst(X1,X2) from(X) -> n__from(X) add(X1,X2) -> n__add(X1,X2) len(X) -> n__len(X) activate(n__fst(X1,X2)) -> fst(X1,X2) activate(n__from(X)) -> from(X) activate(n__add(X1,X2)) -> add(X1,X2) activate(n__len(X)) -> len(X) activate(X) -> X Proof: Matrix Interpretation Processor: dim=1 interpretation: [n__len](x0) = 2x0 + 4, [len](x0) = 4x0 + 6, [n__add](x0, x1) = x0 + 4x1 + 5, [add](x0, x1) = 2x0 + 4x1 + 5, [n__from](x0) = 2x0 + 3, [from](x0) = 4x0 + 3, [n__fst](x0, x1) = 2x0 + x1 + 6, [activate](x0) = 2x0, [cons](x0, x1) = 2x0 + x1, [s](x0) = x0, [nil] = 0, [fst](x0, x1) = 4x0 + 2x1 + 7, [0] = 2 orientation: fst(0(),Z) = 2Z + 15 >= 0 = nil() fst(s(X),cons(Y,Z)) = 4X + 4Y + 2Z + 7 >= 4X + 2Y + 2Z + 6 = cons(Y,n__fst(activate(X),activate(Z))) from(X) = 4X + 3 >= 4X + 3 = cons(X,n__from(s(X))) add(0(),X) = 4X + 9 >= X = X add(s(X),Y) = 2X + 4Y + 5 >= 2X + 4Y + 5 = s(n__add(activate(X),Y)) len(nil()) = 6 >= 2 = 0() len(cons(X,Z)) = 8X + 4Z + 6 >= 4Z + 4 = s(n__len(activate(Z))) fst(X1,X2) = 4X1 + 2X2 + 7 >= 2X1 + X2 + 6 = n__fst(X1,X2) from(X) = 4X + 3 >= 2X + 3 = n__from(X) add(X1,X2) = 2X1 + 4X2 + 5 >= X1 + 4X2 + 5 = n__add(X1,X2) len(X) = 4X + 6 >= 2X + 4 = n__len(X) activate(n__fst(X1,X2)) = 4X1 + 2X2 + 12 >= 4X1 + 2X2 + 7 = fst(X1,X2) activate(n__from(X)) = 4X + 6 >= 4X + 3 = from(X) activate(n__add(X1,X2)) = 2X1 + 8X2 + 10 >= 2X1 + 4X2 + 5 = add(X1,X2) activate(n__len(X)) = 4X + 8 >= 4X + 6 = len(X) activate(X) = 2X >= X = X problem: from(X) -> cons(X,n__from(s(X))) add(s(X),Y) -> s(n__add(activate(X),Y)) from(X) -> n__from(X) add(X1,X2) -> n__add(X1,X2) activate(X) -> X Matrix Interpretation Processor: dim=1 interpretation: [n__add](x0, x1) = x0 + 4x1 + 2, [add](x0, x1) = 6x0 + 4x1 + 2, [n__from](x0) = x0 + 1, [from](x0) = 4x0 + 6, [activate](x0) = x0, [cons](x0, x1) = 3x0 + x1 + 2, [s](x0) = x0 + 3 orientation: from(X) = 4X + 6 >= 4X + 6 = cons(X,n__from(s(X))) add(s(X),Y) = 6X + 4Y + 20 >= X + 4Y + 5 = s(n__add(activate(X),Y)) from(X) = 4X + 6 >= X + 1 = n__from(X) add(X1,X2) = 6X1 + 4X2 + 2 >= X1 + 4X2 + 2 = n__add(X1,X2) activate(X) = X >= X = X problem: from(X) -> cons(X,n__from(s(X))) add(X1,X2) -> n__add(X1,X2) activate(X) -> X Matrix Interpretation Processor: dim=1 interpretation: [n__add](x0, x1) = 2x0 + 4x1, [add](x0, x1) = 2x0 + 4x1 + 1, [n__from](x0) = x0, [from](x0) = 6x0, [activate](x0) = 4x0 + 2, [cons](x0, x1) = 2x0 + 4x1, [s](x0) = x0 orientation: from(X) = 6X >= 6X = cons(X,n__from(s(X))) add(X1,X2) = 2X1 + 4X2 + 1 >= 2X1 + 4X2 = n__add(X1,X2) activate(X) = 4X + 2 >= X = X problem: from(X) -> cons(X,n__from(s(X))) Matrix Interpretation Processor: dim=1 interpretation: [n__from](x0) = 2x0, [from](x0) = 5x0 + 4, [cons](x0, x1) = x0 + x1, [s](x0) = 2x0 orientation: from(X) = 5X + 4 >= 5X = cons(X,n__from(s(X))) problem: Qed