MAYBE

Problem:
 a(x1) -> x1
 a(b(x1)) -> a(a(c(b(b(a(x1))))))
 b(x1) -> x1
 c(c(x1)) -> x1

Proof:
 String Reversal Processor:
  a(x1) -> x1
  b(a(x1)) -> a(b(b(c(a(a(x1))))))
  b(x1) -> x1
  c(c(x1)) -> x1
  DP Processor:
   DPs:
    b#(a(x1)) -> a#(a(x1))
    b#(a(x1)) -> c#(a(a(x1)))
    b#(a(x1)) -> b#(c(a(a(x1))))
    b#(a(x1)) -> b#(b(c(a(a(x1)))))
    b#(a(x1)) -> a#(b(b(c(a(a(x1))))))
   TRS:
    a(x1) -> x1
    b(a(x1)) -> a(b(b(c(a(a(x1))))))
    b(x1) -> x1
    c(c(x1)) -> x1
   TDG Processor:
    DPs:
     b#(a(x1)) -> a#(a(x1))
     b#(a(x1)) -> c#(a(a(x1)))
     b#(a(x1)) -> b#(c(a(a(x1))))
     b#(a(x1)) -> b#(b(c(a(a(x1)))))
     b#(a(x1)) -> a#(b(b(c(a(a(x1))))))
    TRS:
     a(x1) -> x1
     b(a(x1)) -> a(b(b(c(a(a(x1))))))
     b(x1) -> x1
     c(c(x1)) -> x1
    graph:
     b#(a(x1)) -> b#(c(a(a(x1)))) -> b#(a(x1)) -> a#(b(b(c(a(a(x1))))))
     b#(a(x1)) -> b#(c(a(a(x1)))) -> b#(a(x1)) -> b#(b(c(a(a(x1)))))
     b#(a(x1)) -> b#(c(a(a(x1)))) -> b#(a(x1)) -> b#(c(a(a(x1))))
     b#(a(x1)) -> b#(c(a(a(x1)))) -> b#(a(x1)) -> c#(a(a(x1)))
     b#(a(x1)) -> b#(c(a(a(x1)))) -> b#(a(x1)) -> a#(a(x1))
     b#(a(x1)) -> b#(b(c(a(a(x1))))) ->
     b#(a(x1)) -> a#(b(b(c(a(a(x1))))))
     b#(a(x1)) -> b#(b(c(a(a(x1))))) ->
     b#(a(x1)) -> b#(b(c(a(a(x1)))))
     b#(a(x1)) -> b#(b(c(a(a(x1))))) -> b#(a(x1)) -> b#(c(a(a(x1))))
     b#(a(x1)) -> b#(b(c(a(a(x1))))) -> b#(a(x1)) -> c#(a(a(x1)))
     b#(a(x1)) -> b#(b(c(a(a(x1))))) -> b#(a(x1)) -> a#(a(x1))
    SCC Processor:
     #sccs: 1
     #rules: 2
     #arcs: 10/25
     DPs:
      b#(a(x1)) -> b#(c(a(a(x1))))
      b#(a(x1)) -> b#(b(c(a(a(x1)))))
     TRS:
      a(x1) -> x1
      b(a(x1)) -> a(b(b(c(a(a(x1))))))
      b(x1) -> x1
      c(c(x1)) -> x1
     Arctic Interpretation Processor:
      dimension: 2
      interpretation:
       [b#](x0) = [-& 0 ]x0 + [0],
       
                 [0  0 ]     [1 ]
       [c](x0) = [0  -&]x0 + [-&],
       
                 [0 0]     [0]
       [b](x0) = [0 1]x0 + [0],
       
                 [0  -&]     [-&]
       [a](x0) = [1  0 ]x0 + [1 ]
      orientation:
       b#(a(x1)) = [1 0]x1 + [1] >= [0  -&]x1 + [0] = b#(c(a(a(x1))))
       
       b#(a(x1)) = [1 0]x1 + [1] >= [1 0]x1 + [1] = b#(b(c(a(a(x1)))))
       
               [0  -&]     [-&]           
       a(x1) = [1  0 ]x1 + [1 ] >= x1 = x1
       
                  [1 0]     [1]    [1 0]     [1]                       
       b(a(x1)) = [2 1]x1 + [2] >= [2 1]x1 + [2] = a(b(b(c(a(a(x1))))))
       
               [0 0]     [0]           
       b(x1) = [0 1]x1 + [0] >= x1 = x1
       
                  [0 0]     [1]           
       c(c(x1)) = [0 0]x1 + [1] >= x1 = x1
      problem:
       DPs:
        b#(a(x1)) -> b#(b(c(a(a(x1)))))
       TRS:
        a(x1) -> x1
        b(a(x1)) -> a(b(b(c(a(a(x1))))))
        b(x1) -> x1
        c(c(x1)) -> x1
      Open