YES Problem: a(x1) -> x1 a(b(x1)) -> b(c(a(x1))) c(x1) -> b(x1) c(c(x1)) -> a(c(x1)) Proof: String Reversal Processor: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) DP Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(b(x1)) b#(a(x1)) -> a#(c(b(x1))) c#(x1) -> b#(x1) c#(c(x1)) -> a#(x1) c#(c(x1)) -> c#(a(x1)) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) TDG Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(b(x1)) b#(a(x1)) -> a#(c(b(x1))) c#(x1) -> b#(x1) c#(c(x1)) -> a#(x1) c#(c(x1)) -> c#(a(x1)) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) graph: c#(c(x1)) -> c#(a(x1)) -> c#(c(x1)) -> c#(a(x1)) c#(c(x1)) -> c#(a(x1)) -> c#(c(x1)) -> a#(x1) c#(c(x1)) -> c#(a(x1)) -> c#(x1) -> b#(x1) c#(x1) -> b#(x1) -> b#(a(x1)) -> a#(c(b(x1))) c#(x1) -> b#(x1) -> b#(a(x1)) -> c#(b(x1)) c#(x1) -> b#(x1) -> b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(b(x1)) -> c#(c(x1)) -> c#(a(x1)) b#(a(x1)) -> c#(b(x1)) -> c#(c(x1)) -> a#(x1) b#(a(x1)) -> c#(b(x1)) -> c#(x1) -> b#(x1) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> a#(c(b(x1))) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> c#(b(x1)) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) SCC Processor: #sccs: 1 #rules: 4 #arcs: 12/36 DPs: c#(c(x1)) -> c#(a(x1)) c#(x1) -> b#(x1) b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(b(x1)) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) Arctic Interpretation Processor: dimension: 2 interpretation: [c#](x0) = [0 0]x0 + [1], [b#](x0) = [0 0]x0 + [1], [1 1] [2] [c](x0) = [0 0]x0 + [0], [-& 0 ] [0] [b](x0) = [-& 0 ]x0 + [0], [0 0 ] [0] [a](x0) = [-& 1 ]x0 + [2] orientation: c#(c(x1)) = [1 1]x1 + [2] >= [0 1]x1 + [2] = c#(a(x1)) c#(x1) = [0 0]x1 + [1] >= [0 0]x1 + [1] = b#(x1) b#(a(x1)) = [0 1]x1 + [2] >= [0 0]x1 + [1] = b#(x1) b#(a(x1)) = [0 1]x1 + [2] >= [-& 0 ]x1 + [1] = c#(b(x1)) [0 0 ] [0] a(x1) = [-& 1 ]x1 + [2] >= x1 = x1 [-& 1 ] [2] [-& 1 ] [2] b(a(x1)) = [-& 1 ]x1 + [2] >= [-& 1 ]x1 + [2] = a(c(b(x1))) [1 1] [2] [-& 0 ] [0] c(x1) = [0 0]x1 + [0] >= [-& 0 ]x1 + [0] = b(x1) [2 2] [3] [1 2] [3] c(c(x1)) = [1 1]x1 + [2] >= [0 1]x1 + [2] = c(a(x1)) problem: DPs: c#(c(x1)) -> c#(a(x1)) c#(x1) -> b#(x1) b#(a(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) EDG Processor: DPs: c#(c(x1)) -> c#(a(x1)) c#(x1) -> b#(x1) b#(a(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) graph: c#(c(x1)) -> c#(a(x1)) -> c#(x1) -> b#(x1) c#(c(x1)) -> c#(a(x1)) -> c#(c(x1)) -> c#(a(x1)) c#(x1) -> b#(x1) -> b#(a(x1)) -> b#(x1) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) CDG Processor: DPs: c#(c(x1)) -> c#(a(x1)) c#(x1) -> b#(x1) b#(a(x1)) -> b#(x1) TRS: a(x1) -> x1 b(a(x1)) -> a(c(b(x1))) c(x1) -> b(x1) c(c(x1)) -> c(a(x1)) graph: c#(c(x1)) -> c#(a(x1)) -> c#(x1) -> b#(x1) SCC Processor: #sccs: 0 #rules: 0 #arcs: 1/9