YES Problem: a(x1) -> x1 a(b(b(x1))) -> b(b(b(c(x1)))) c(b(x1)) -> a(a(x1)) Proof: String Reversal Processor: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) DP Processor: DPs: b#(b(a(x1))) -> b#(x1) b#(b(a(x1))) -> b#(b(x1)) b#(b(a(x1))) -> b#(b(b(x1))) b#(c(x1)) -> a#(x1) b#(c(x1)) -> a#(a(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) TDG Processor: DPs: b#(b(a(x1))) -> b#(x1) b#(b(a(x1))) -> b#(b(x1)) b#(b(a(x1))) -> b#(b(b(x1))) b#(c(x1)) -> a#(x1) b#(c(x1)) -> a#(a(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) graph: b#(b(a(x1))) -> b#(b(b(x1))) -> b#(c(x1)) -> a#(a(x1)) b#(b(a(x1))) -> b#(b(b(x1))) -> b#(c(x1)) -> a#(x1) b#(b(a(x1))) -> b#(b(b(x1))) -> b#(b(a(x1))) -> b#(b(b(x1))) b#(b(a(x1))) -> b#(b(b(x1))) -> b#(b(a(x1))) -> b#(b(x1)) b#(b(a(x1))) -> b#(b(b(x1))) -> b#(b(a(x1))) -> b#(x1) b#(b(a(x1))) -> b#(b(x1)) -> b#(c(x1)) -> a#(a(x1)) b#(b(a(x1))) -> b#(b(x1)) -> b#(c(x1)) -> a#(x1) b#(b(a(x1))) -> b#(b(x1)) -> b#(b(a(x1))) -> b#(b(b(x1))) b#(b(a(x1))) -> b#(b(x1)) -> b#(b(a(x1))) -> b#(b(x1)) b#(b(a(x1))) -> b#(b(x1)) -> b#(b(a(x1))) -> b#(x1) b#(b(a(x1))) -> b#(x1) -> b#(c(x1)) -> a#(a(x1)) b#(b(a(x1))) -> b#(x1) -> b#(c(x1)) -> a#(x1) b#(b(a(x1))) -> b#(x1) -> b#(b(a(x1))) -> b#(b(b(x1))) b#(b(a(x1))) -> b#(x1) -> b#(b(a(x1))) -> b#(b(x1)) b#(b(a(x1))) -> b#(x1) -> b#(b(a(x1))) -> b#(x1) SCC Processor: #sccs: 1 #rules: 3 #arcs: 15/25 DPs: b#(b(a(x1))) -> b#(b(b(x1))) b#(b(a(x1))) -> b#(x1) b#(b(a(x1))) -> b#(b(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) Arctic Interpretation Processor: dimension: 3 interpretation: [b#](x0) = [0 0 -&]x0 + [0], [-& -& 0 ] [0] [c](x0) = [-& -& 0 ]x0 + [1] [0 0 1 ] [1], [-& -& 0 ] [0] [b](x0) = [1 -& 0 ]x0 + [0] [0 0 -&] [1], [0 0 1 ] [1 ] [a](x0) = [-& 0 0 ]x0 + [-&] [-& -& 0 ] [0 ] orientation: b#(b(a(x1))) = [1 1 2]x1 + [2] >= [0 0 1]x1 + [1] = b#(b(b(x1))) b#(b(a(x1))) = [1 1 2]x1 + [2] >= [0 0 -&]x1 + [0] = b#(x1) b#(b(a(x1))) = [1 1 2]x1 + [2] >= [1 -& 0 ]x1 + [0] = b#(b(x1)) [0 0 1 ] [1 ] a(x1) = [-& 0 0 ]x1 + [-&] >= x1 = x1 [-& -& 0 ] [0 ] [0 0 1] [1] [0 0 1] [1] b(b(a(x1))) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = c(b(b(b(x1)))) [1 1 2] [2] [1 1 2] [2] [0 0 1 ] [1] [0 0 1 ] [1] b(c(x1)) = [0 0 1 ]x1 + [1] >= [-& 0 0 ]x1 + [0] = a(a(x1)) [-& -& 0 ] [1] [-& -& 0 ] [0] problem: DPs: b#(b(a(x1))) -> b#(b(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) EDG Processor: DPs: b#(b(a(x1))) -> b#(b(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) graph: b#(b(a(x1))) -> b#(b(x1)) -> b#(b(a(x1))) -> b#(b(x1)) CDG Processor: DPs: b#(b(a(x1))) -> b#(b(x1)) TRS: a(x1) -> x1 b(b(a(x1))) -> c(b(b(b(x1)))) b(c(x1)) -> a(a(x1)) graph: Qed