YES Problem: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) Proof: DP Processor: DPs: a#(x1) -> c#(x1) a#(x1) -> b#(c(x1)) c#(c(b(x1))) -> c#(x1) c#(c(b(x1))) -> a#(c(x1)) c#(c(b(x1))) -> c#(a(c(x1))) c#(c(b(x1))) -> b#(c(a(c(x1)))) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) TDG Processor: DPs: a#(x1) -> c#(x1) a#(x1) -> b#(c(x1)) c#(c(b(x1))) -> c#(x1) c#(c(b(x1))) -> a#(c(x1)) c#(c(b(x1))) -> c#(a(c(x1))) c#(c(b(x1))) -> b#(c(a(c(x1)))) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) graph: c#(c(b(x1))) -> c#(a(c(x1))) -> c#(c(b(x1))) -> b#(c(a(c(x1)))) c#(c(b(x1))) -> c#(a(c(x1))) -> c#(c(b(x1))) -> c#(a(c(x1))) c#(c(b(x1))) -> c#(a(c(x1))) -> c#(c(b(x1))) -> a#(c(x1)) c#(c(b(x1))) -> c#(a(c(x1))) -> c#(c(b(x1))) -> c#(x1) c#(c(b(x1))) -> c#(x1) -> c#(c(b(x1))) -> b#(c(a(c(x1)))) c#(c(b(x1))) -> c#(x1) -> c#(c(b(x1))) -> c#(a(c(x1))) c#(c(b(x1))) -> c#(x1) -> c#(c(b(x1))) -> a#(c(x1)) c#(c(b(x1))) -> c#(x1) -> c#(c(b(x1))) -> c#(x1) c#(c(b(x1))) -> a#(c(x1)) -> a#(x1) -> b#(c(x1)) c#(c(b(x1))) -> a#(c(x1)) -> a#(x1) -> c#(x1) a#(x1) -> c#(x1) -> c#(c(b(x1))) -> b#(c(a(c(x1)))) a#(x1) -> c#(x1) -> c#(c(b(x1))) -> c#(a(c(x1))) a#(x1) -> c#(x1) -> c#(c(b(x1))) -> a#(c(x1)) a#(x1) -> c#(x1) -> c#(c(b(x1))) -> c#(x1) SCC Processor: #sccs: 1 #rules: 4 #arcs: 14/36 DPs: c#(c(b(x1))) -> c#(a(c(x1))) c#(c(b(x1))) -> c#(x1) c#(c(b(x1))) -> a#(c(x1)) a#(x1) -> c#(x1) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) Arctic Interpretation Processor: dimension: 2 interpretation: [c#](x0) = [1 0]x0 + [0], [a#](x0) = [1 0]x0 + [0], [-& 0 ] [0] [b](x0) = [0 2 ]x0 + [3], [-& 0 ] [1 ] [c](x0) = [0 -&]x0 + [-&], [0 -&] [1] [a](x0) = [2 0 ]x0 + [3] orientation: c#(c(b(x1))) = [1 3]x1 + [4] >= [0 2]x1 + [3] = c#(a(c(x1))) c#(c(b(x1))) = [1 3]x1 + [4] >= [1 0]x1 + [0] = c#(x1) c#(c(b(x1))) = [1 3]x1 + [4] >= [0 1]x1 + [2] = a#(c(x1)) a#(x1) = [1 0]x1 + [0] >= [1 0]x1 + [0] = c#(x1) [0 -&] [1] [0 -&] [0] a(x1) = [2 0 ]x1 + [3] >= [2 0 ]x1 + [3] = b(c(x1)) [0 2] [3] b(b(x1)) = [2 4]x1 + [5] >= x1 = x1 [-& 0 ] [1] [-& 0 ] [1] c(c(b(x1))) = [0 2 ]x1 + [3] >= [0 2 ]x1 + [3] = b(c(a(c(x1)))) problem: DPs: c#(c(b(x1))) -> c#(x1) a#(x1) -> c#(x1) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) EDG Processor: DPs: c#(c(b(x1))) -> c#(x1) a#(x1) -> c#(x1) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) graph: c#(c(b(x1))) -> c#(x1) -> c#(c(b(x1))) -> c#(x1) a#(x1) -> c#(x1) -> c#(c(b(x1))) -> c#(x1) CDG Processor: DPs: c#(c(b(x1))) -> c#(x1) a#(x1) -> c#(x1) TRS: a(x1) -> b(c(x1)) b(b(x1)) -> x1 c(c(b(x1))) -> b(c(a(c(x1)))) graph: Qed