YES Problem: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) Proof: DP Processor: DPs: a#(a(x1)) -> c#(x1) a#(a(x1)) -> a#(b(b(c(x1)))) c#(b(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) TDG Processor: DPs: a#(a(x1)) -> c#(x1) a#(a(x1)) -> a#(b(b(c(x1)))) c#(b(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) graph: c#(b(x1)) -> c#(x1) -> c#(b(x1)) -> a#(c(x1)) c#(b(x1)) -> c#(x1) -> c#(b(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) -> a#(a(x1)) -> a#(b(b(c(x1)))) c#(b(x1)) -> a#(c(x1)) -> a#(a(x1)) -> c#(x1) a#(a(x1)) -> c#(x1) -> c#(b(x1)) -> a#(c(x1)) a#(a(x1)) -> c#(x1) -> c#(b(x1)) -> c#(x1) a#(a(x1)) -> a#(b(b(c(x1)))) -> a#(a(x1)) -> a#(b(b(c(x1)))) a#(a(x1)) -> a#(b(b(c(x1)))) -> a#(a(x1)) -> c#(x1) EDG Processor: DPs: a#(a(x1)) -> c#(x1) a#(a(x1)) -> a#(b(b(c(x1)))) c#(b(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) graph: c#(b(x1)) -> c#(x1) -> c#(b(x1)) -> c#(x1) c#(b(x1)) -> c#(x1) -> c#(b(x1)) -> a#(c(x1)) c#(b(x1)) -> a#(c(x1)) -> a#(a(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) -> a#(a(x1)) -> a#(b(b(c(x1)))) a#(a(x1)) -> c#(x1) -> c#(b(x1)) -> c#(x1) a#(a(x1)) -> c#(x1) -> c#(b(x1)) -> a#(c(x1)) SCC Processor: #sccs: 1 #rules: 3 #arcs: 6/16 DPs: c#(b(x1)) -> c#(x1) c#(b(x1)) -> a#(c(x1)) a#(a(x1)) -> c#(x1) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) Arctic Interpretation Processor: dimension: 2 interpretation: [c#](x0) = [3 0]x0, [a#](x0) = [-& 3 ]x0 + [0], [1 0 ] [1] [b](x0) = [0 -&]x0 + [1], [-& 0 ] [0 ] [c](x0) = [0 -&]x0 + [-&], [-& 0 ] [1] [a](x0) = [0 1 ]x0 + [1] orientation: c#(b(x1)) = [4 3]x1 + [4] >= [3 0]x1 = c#(x1) c#(b(x1)) = [4 3]x1 + [4] >= [3 -&]x1 + [0] = a#(c(x1)) a#(a(x1)) = [3 4]x1 + [4] >= [3 0]x1 = c#(x1) [0 1] [1] [0 1] [1] a(a(x1)) = [1 2]x1 + [2] >= [1 2]x1 + [2] = a(b(b(c(x1)))) [0 1 ] [1] c(a(x1)) = [-& 0 ]x1 + [1] >= x1 = x1 [0 -&] [1] [0 -&] [1] c(b(x1)) = [1 0 ]x1 + [1] >= [1 0 ]x1 + [1] = a(c(x1)) problem: DPs: a#(a(x1)) -> c#(x1) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) EDG Processor: DPs: a#(a(x1)) -> c#(x1) TRS: a(a(x1)) -> a(b(b(c(x1)))) c(a(x1)) -> x1 c(b(x1)) -> a(c(x1)) graph: Qed