YES

Problem:
 b(a(b(b(a(b(a(x1))))))) -> a(b(a(a(b(b(a(b(b(a(x1))))))))))

Proof:
 String Reversal Processor:
  a(b(a(b(b(a(b(x1))))))) -> a(b(b(a(b(b(a(a(b(a(x1))))))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {3}
    transitions:
     a1(50) -> 51*
     a1(15) -> 16*
     a1(82) -> 83*
     a1(32) -> 33*
     a1(17) -> 18*
     a1(29) -> 30*
     a1(24) -> 25*
     a1(46) -> 47*
     a1(26) -> 27*
     a1(21) -> 22*
     a1(28) -> 29*
     a1(18) -> 19*
     b1(30) -> 31*
     b1(20) -> 21*
     b1(27) -> 28*
     b1(22) -> 23*
     b1(19) -> 20*
     b1(31) -> 32*
     b1(16) -> 17*
     b1(33) -> 34*
     b1(23) -> 24*
     a2(55) -> 56*
     a2(52) -> 53*
     a2(54) -> 55*
     a2(76) -> 77*
     a2(61) -> 62*
     a2(58) -> 59*
     a2(80) -> 81*
     a0(3) -> 3*
     b2(60) -> 61*
     b2(57) -> 58*
     b2(59) -> 60*
     b2(56) -> 57*
     b2(53) -> 54*
     b0(3) -> 3*
     3 -> 15*
     16 -> 50*
     18 -> 16,3,15
     20 -> 76,46
     23 -> 26*
     25 -> 16,18,3
     31 -> 52*
     34 -> 16*
     47 -> 16*
     51 -> 16*
     57 -> 80*
     60 -> 82*
     62 -> 18,3,15,16
     77 -> 53*
     81 -> 53*
     83 -> 16*
   problem:
    
   Qed