YES

Problem:
 c(a(b(a(x1)))) -> a(b(a(a(c(a(b(c(a(b(x1))))))))))

Proof:
 String Reversal Processor:
  a(b(a(c(x1)))) -> b(a(c(b(a(c(a(a(b(a(x1))))))))))
  Bounds Processor:
   bound: 3
   enrichment: match
   automaton:
    final states: {4}
    transitions:
     b3(65) -> 66*
     b3(60) -> 61*
     b3(87) -> 88*
     b3(82) -> 83*
     b3(68) -> 69*
     b3(90) -> 91*
     b1(25) -> 26*
     b1(22) -> 23*
     b1(17) -> 18*
     a3(67) -> 68*
     a3(62) -> 63*
     a3(89) -> 90*
     a3(84) -> 85*
     a3(64) -> 65*
     a3(59) -> 60*
     a3(86) -> 87*
     a3(81) -> 82*
     a3(61) -> 62*
     a3(83) -> 84*
     a1(24) -> 25*
     a1(19) -> 20*
     a1(31) -> 32*
     a1(21) -> 22*
     a1(16) -> 17*
     a1(18) -> 19*
     c3(66) -> 67*
     c3(88) -> 89*
     c3(63) -> 64*
     c3(85) -> 86*
     c1(20) -> 21*
     c1(23) -> 24*
     b2(42) -> 43*
     b2(39) -> 40*
     b2(34) -> 35*
     a0(4) -> 4*
     a2(55) -> 56*
     a2(35) -> 36*
     a2(41) -> 42*
     a2(36) -> 37*
     a2(38) -> 39*
     a2(33) -> 34*
     b0(4) -> 4*
     c2(40) -> 41*
     c2(37) -> 38*
     c0(4) -> 4*
     4 -> 16*
     20 -> 55*
     23 -> 33,31
     26 -> 17,19,4
     32 -> 17*
     37 -> 81*
     40 -> 59*
     43 -> 34,32,20,17
     56 -> 34*
     69 -> 56,34
     91 -> 60*
   problem:
    
   Qed