YES

Problem:
 b(a(b(a(c(b(a(x1))))))) -> a(b(a(c(b(b(a(b(a(c(x1))))))))))

Proof:
 String Reversal Processor:
  a(b(c(a(b(a(b(x1))))))) -> c(a(b(a(b(b(c(a(b(a(x1))))))))))
  Bounds Processor:
   bound: 3
   enrichment: match
   automaton:
    final states: {4}
    transitions:
     c3(92) -> 93*
     c3(86) -> 87*
     c1(25) -> 26*
     c1(19) -> 20*
     a3(89) -> 90*
     a3(91) -> 92*
     a3(83) -> 84*
     a3(85) -> 86*
     a1(27) -> 28*
     a1(22) -> 23*
     a1(24) -> 25*
     a1(16) -> 17*
     a1(18) -> 19*
     b3(87) -> 88*
     b3(84) -> 85*
     b3(88) -> 89*
     b3(90) -> 91*
     b1(20) -> 21*
     b1(17) -> 18*
     b1(21) -> 22*
     b1(23) -> 24*
     c2(55) -> 56*
     c2(42) -> 43*
     c2(49) -> 50*
     c2(36) -> 37*
     a0(4) -> 4*
     a2(35) -> 36*
     a2(52) -> 53*
     a2(54) -> 55*
     a2(39) -> 40*
     a2(46) -> 47*
     a2(41) -> 42*
     a2(68) -> 69*
     a2(48) -> 49*
     a2(33) -> 34*
     b0(4) -> 4*
     b2(50) -> 51*
     b2(40) -> 41*
     b2(47) -> 48*
     b2(37) -> 38*
     b2(34) -> 35*
     b2(51) -> 52*
     b2(53) -> 54*
     b2(38) -> 39*
     c0(4) -> 4*
     4 -> 16*
     20 -> 33*
     21 -> 46,27
     26 -> 47,28,17,4
     28 -> 17*
     38 -> 83,68
     43 -> 47,28,17
     56 -> 49,19
     69 -> 47*
     93 -> 49*
   problem:
    
   Qed