YES

Problem:
 b(a(b(a(b(b(x1)))))) -> a(b(a(b(b(b(a(x1)))))))

Proof:
 String Reversal Processor:
  b(b(a(b(a(b(x1)))))) -> a(b(b(b(a(b(a(x1)))))))
  Bounds Processor:
   bound: 3
   enrichment: match
   automaton:
    final states: {3}
    transitions:
     a3(72) -> 73*
     a3(66) -> 67*
     a3(68) -> 69*
     a1(20) -> 21*
     a1(42) -> 43*
     a1(12) -> 13*
     a1(14) -> 15*
     a1(18) -> 19*
     b3(70) -> 71*
     b3(67) -> 68*
     b3(69) -> 70*
     b3(71) -> 72*
     b1(15) -> 16*
     b1(17) -> 18*
     b1(16) -> 17*
     b1(13) -> 14*
     a2(52) -> 53*
     a2(32) -> 33*
     a2(54) -> 55*
     a2(46) -> 47*
     a2(26) -> 27*
     a2(48) -> 49*
     a2(28) -> 29*
     b0(3) -> 3*
     b2(50) -> 51*
     b2(30) -> 31*
     b2(47) -> 48*
     b2(27) -> 28*
     b2(49) -> 50*
     b2(29) -> 30*
     b2(51) -> 52*
     b2(31) -> 32*
     a0(3) -> 3*
     3 -> 12*
     15 -> 46*
     16 -> 26*
     17 -> 20*
     19 -> 17,3
     21 -> 13*
     29 -> 66*
     30 -> 54*
     31 -> 42*
     33 -> 17,20
     43 -> 13*
     53 -> 31*
     55 -> 27*
     73 -> 31,42
   problem:
    
   Qed