YES

Problem:
 b(a(b(b(b(b(x1)))))) -> a(b(b(b(b(b(a(x1)))))))

Proof:
 String Reversal Processor:
  b(b(b(b(a(b(x1)))))) -> a(b(b(b(b(b(a(x1)))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {3}
    transitions:
     a1(20) -> 21*
     a1(12) -> 13*
     a1(18) -> 19*
     b1(15) -> 16*
     b1(17) -> 18*
     b1(14) -> 15*
     b1(16) -> 17*
     b1(13) -> 14*
     a2(72) -> 73*
     a2(42) -> 43*
     a2(32) -> 33*
     a2(64) -> 65*
     a2(66) -> 67*
     a2(26) -> 27*
     a2(58) -> 59*
     a2(48) -> 49*
     b0(3) -> 3*
     b2(70) -> 71*
     b2(60) -> 61*
     b2(45) -> 46*
     b2(30) -> 31*
     b2(67) -> 68*
     b2(62) -> 63*
     b2(47) -> 48*
     b2(27) -> 28*
     b2(69) -> 70*
     b2(59) -> 60*
     b2(44) -> 45*
     b2(29) -> 30*
     b2(71) -> 72*
     b2(61) -> 62*
     b2(46) -> 47*
     b2(31) -> 32*
     b2(68) -> 69*
     b2(63) -> 64*
     b2(43) -> 44*
     b2(28) -> 29*
     a0(3) -> 3*
     3 -> 12*
     13 -> 66*
     14 -> 58*
     15 -> 42*
     16 -> 26*
     17 -> 20*
     19 -> 17,3
     21 -> 13*
     33 -> 17,20
     49 -> 31*
     65 -> 47*
     73 -> 63*
   problem:
    
   Qed