YES

Problem:
 b(a(c(b(b(x1))))) -> a(c(b(b(b(a(c(x1)))))))

Proof:
 String Reversal Processor:
  b(b(c(a(b(x1))))) -> c(a(b(b(b(c(a(x1)))))))
  Bounds Processor:
   bound: 2
   enrichment: match
   automaton:
    final states: {4}
    transitions:
     c1(19) -> 20*
     c1(14) -> 15*
     a1(21) -> 22*
     a1(18) -> 19*
     a1(13) -> 14*
     b1(15) -> 16*
     b1(17) -> 18*
     b1(16) -> 17*
     c2(43) -> 44*
     c2(38) -> 39*
     c2(33) -> 34*
     c2(28) -> 29*
     b0(4) -> 4*
     a2(42) -> 43*
     a2(37) -> 38*
     a2(32) -> 33*
     a2(27) -> 28*
     c0(4) -> 4*
     b2(40) -> 41*
     b2(30) -> 31*
     b2(39) -> 40*
     b2(29) -> 30*
     b2(41) -> 42*
     b2(31) -> 32*
     a0(4) -> 4*
     4 -> 13*
     15 -> 37*
     16 -> 27*
     17 -> 21*
     20 -> 17,4
     22 -> 14*
     34 -> 17,21
     44 -> 31*
   problem:
    
   Qed