YES

Problem:
 t(f(x1)) -> t(c(n(x1)))
 n(f(x1)) -> f(n(x1))
 o(f(x1)) -> f(o(x1))
 n(s(x1)) -> f(s(x1))
 o(s(x1)) -> f(s(x1))
 c(f(x1)) -> f(c(x1))
 c(n(x1)) -> n(c(x1))
 c(o(x1)) -> o(c(x1))
 c(o(x1)) -> o(x1)

Proof:
 Arctic Interpretation Processor:
  dimension: 1
  interpretation:
   [s](x0) = 3x0,
   
   [o](x0) = 5x0,
   
   [c](x0) = x0,
   
   [n](x0) = x0,
   
   [t](x0) = x0,
   
   [f](x0) = x0
  orientation:
   t(f(x1)) = x1 >= x1 = t(c(n(x1)))
   
   n(f(x1)) = x1 >= x1 = f(n(x1))
   
   o(f(x1)) = 5x1 >= 5x1 = f(o(x1))
   
   n(s(x1)) = 3x1 >= 3x1 = f(s(x1))
   
   o(s(x1)) = 8x1 >= 3x1 = f(s(x1))
   
   c(f(x1)) = x1 >= x1 = f(c(x1))
   
   c(n(x1)) = x1 >= x1 = n(c(x1))
   
   c(o(x1)) = 5x1 >= 5x1 = o(c(x1))
   
   c(o(x1)) = 5x1 >= 5x1 = o(x1)
  problem:
   t(f(x1)) -> t(c(n(x1)))
   n(f(x1)) -> f(n(x1))
   o(f(x1)) -> f(o(x1))
   n(s(x1)) -> f(s(x1))
   c(f(x1)) -> f(c(x1))
   c(n(x1)) -> n(c(x1))
   c(o(x1)) -> o(c(x1))
   c(o(x1)) -> o(x1)
  Matrix Interpretation Processor: dim=1
   
   interpretation:
    [s](x0) = 4x0 + 3,
    
    [o](x0) = 4x0,
    
    [c](x0) = x0,
    
    [n](x0) = 4x0 + 1,
    
    [t](x0) = x0 + 8,
    
    [f](x0) = 4x0 + 1
   orientation:
    t(f(x1)) = 4x1 + 9 >= 4x1 + 9 = t(c(n(x1)))
    
    n(f(x1)) = 16x1 + 5 >= 16x1 + 5 = f(n(x1))
    
    o(f(x1)) = 16x1 + 4 >= 16x1 + 1 = f(o(x1))
    
    n(s(x1)) = 16x1 + 13 >= 16x1 + 13 = f(s(x1))
    
    c(f(x1)) = 4x1 + 1 >= 4x1 + 1 = f(c(x1))
    
    c(n(x1)) = 4x1 + 1 >= 4x1 + 1 = n(c(x1))
    
    c(o(x1)) = 4x1 >= 4x1 = o(c(x1))
    
    c(o(x1)) = 4x1 >= 4x1 = o(x1)
   problem:
    t(f(x1)) -> t(c(n(x1)))
    n(f(x1)) -> f(n(x1))
    n(s(x1)) -> f(s(x1))
    c(f(x1)) -> f(c(x1))
    c(n(x1)) -> n(c(x1))
    c(o(x1)) -> o(c(x1))
    c(o(x1)) -> o(x1)
   String Reversal Processor:
    f(t(x1)) -> n(c(t(x1)))
    f(n(x1)) -> n(f(x1))
    s(n(x1)) -> s(f(x1))
    f(c(x1)) -> c(f(x1))
    n(c(x1)) -> c(n(x1))
    o(c(x1)) -> c(o(x1))
    o(c(x1)) -> o(x1)
    Matrix Interpretation Processor: dim=3
     
     interpretation:
                [1 1 1]     [1]
      [s](x0) = [0 1 1]x0 + [0]
                [0 0 0]     [0],
      
                [1 0 0]  
      [o](x0) = [0 0 0]x0
                [1 0 0]  ,
      
                [1 0 0]  
      [c](x0) = [0 0 0]x0
                [0 0 0]  ,
      
                [1 0 0]     [0]
      [n](x0) = [0 0 1]x0 + [1]
                [0 0 1]     [1],
      
                [1 1 0]     [0]
      [t](x0) = [0 0 0]x0 + [0]
                [0 0 0]     [1],
      
                [1 0 0]     [1]
      [f](x0) = [0 0 1]x0 + [0]
                [0 0 1]     [0]
     orientation:
                 [1 1 0]     [1]    [1 1 0]     [0]              
      f(t(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = n(c(t(x1)))
                 [0 0 0]     [1]    [0 0 0]     [1]              
      
                 [1 0 0]     [1]    [1 0 0]     [1]           
      f(n(x1)) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = n(f(x1))
                 [0 0 1]     [1]    [0 0 1]     [1]           
      
                 [1 0 2]     [3]    [1 0 2]     [2]           
      s(n(x1)) = [0 0 2]x1 + [2] >= [0 0 2]x1 + [0] = s(f(x1))
                 [0 0 0]     [0]    [0 0 0]     [0]           
      
                 [1 0 0]     [1]    [1 0 0]     [1]           
      f(c(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = c(f(x1))
                 [0 0 0]     [0]    [0 0 0]     [0]           
      
                 [1 0 0]     [0]    [1 0 0]             
      n(c(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = c(n(x1))
                 [0 0 0]     [1]    [0 0 0]             
      
                 [1 0 0]      [1 0 0]             
      o(c(x1)) = [0 0 0]x1 >= [0 0 0]x1 = c(o(x1))
                 [1 0 0]      [0 0 0]             
      
                 [1 0 0]      [1 0 0]          
      o(c(x1)) = [0 0 0]x1 >= [0 0 0]x1 = o(x1)
                 [1 0 0]      [1 0 0]          
     problem:
      f(n(x1)) -> n(f(x1))
      f(c(x1)) -> c(f(x1))
      n(c(x1)) -> c(n(x1))
      o(c(x1)) -> c(o(x1))
      o(c(x1)) -> o(x1)
     Arctic Interpretation Processor:
      dimension: 2
      interpretation:
                 [0  -&]  
       [o](x0) = [2  0 ]x0,
       
                 [3  1 ]  
       [c](x0) = [-& 3 ]x0,
       
                 [0 1]  
       [n](x0) = [0 0]x0,
       
                 [0 2]  
       [f](x0) = [1 0]x0
      orientation:
                  [2 2]      [2 2]             
       f(n(x1)) = [1 2]x1 >= [1 2]x1 = n(f(x1))
       
                  [3 5]      [3 5]             
       f(c(x1)) = [4 3]x1 >= [4 3]x1 = c(f(x1))
       
                  [3 4]      [3 4]             
       n(c(x1)) = [3 3]x1 >= [3 3]x1 = c(n(x1))
       
                  [3 1]      [3 1]             
       o(c(x1)) = [5 3]x1 >= [5 3]x1 = c(o(x1))
       
                  [3 1]      [0  -&]          
       o(c(x1)) = [5 3]x1 >= [2  0 ]x1 = o(x1)
      problem:
       f(n(x1)) -> n(f(x1))
       f(c(x1)) -> c(f(x1))
       n(c(x1)) -> c(n(x1))
       o(c(x1)) -> c(o(x1))
      KBO Processor:
       weight function:
        w0 = 1
        w(o) = w(c) = w(n) = w(f) = 1
       precedence:
        f > o ~ n > c
       problem:
        
       Qed