YES

Problem:
 a(f(),a(f(),x)) -> a(x,x)
 a(h(),x) -> a(f(),a(g(),a(f(),x)))

Proof:
 Uncurry Processor:
  f1(f1(x)) -> a(x,x)
  h1(x) -> f1(g1(f1(x)))
  a(f(),x1) -> f1(x1)
  a(h(),x1) -> h1(x1)
  a(g(),x1) -> g1(x1)
  Matrix Interpretation Processor: dim=3
   
   interpretation:
               [1 0 0]  
    [g1](x0) = [0 0 0]x0
               [0 0 0]  ,
    
               [1 1 0]     [1]
    [h1](x0) = [1 1 0]x0 + [1]
               [0 0 0]     [0],
    
               [1 1 0]  
    [f1](x0) = [1 1 0]x0
               [0 0 0]  ,
    
          [0]
    [g] = [1]
          [0],
    
          [1]
    [h] = [1]
          [0],
    
                  [1 0 0]     [1 1 0]  
    [a](x0, x1) = [1 1 0]x0 + [1 1 0]x1
                  [0 0 0]     [0 0 0]  ,
    
          [0]
    [f] = [1]
          [0]
   orientation:
                [2 2 0]     [2 1 0]          
    f1(f1(x)) = [2 2 0]x >= [2 2 0]x = a(x,x)
                [0 0 0]     [0 0 0]          
    
            [1 1 0]    [1]    [1 1 0]                 
    h1(x) = [1 1 0]x + [1] >= [1 1 0]x = f1(g1(f1(x)))
            [0 0 0]    [0]    [0 0 0]                 
    
                [1 1 0]     [0]    [1 1 0]           
    a(f(),x1) = [1 1 0]x1 + [1] >= [1 1 0]x1 = f1(x1)
                [0 0 0]     [0]    [0 0 0]           
    
                [1 1 0]     [1]    [1 1 0]     [1]         
    a(h(),x1) = [1 1 0]x1 + [2] >= [1 1 0]x1 + [1] = h1(x1)
                [0 0 0]     [0]    [0 0 0]     [0]         
    
                [1 1 0]     [0]    [1 0 0]           
    a(g(),x1) = [1 1 0]x1 + [1] >= [0 0 0]x1 = g1(x1)
                [0 0 0]     [0]    [0 0 0]           
   problem:
    f1(f1(x)) -> a(x,x)
    a(f(),x1) -> f1(x1)
    a(h(),x1) -> h1(x1)
    a(g(),x1) -> g1(x1)
   Matrix Interpretation Processor: dim=1
    
    interpretation:
     [g1](x0) = 2x0,
     
     [h1](x0) = 2x0,
     
     [f1](x0) = 2x0,
     
     [g] = 0,
     
     [h] = 0,
     
     [a](x0, x1) = 2x0 + 2x1,
     
     [f] = 1
    orientation:
     f1(f1(x)) = 4x >= 4x = a(x,x)
     
     a(f(),x1) = 2x1 + 2 >= 2x1 = f1(x1)
     
     a(h(),x1) = 2x1 >= 2x1 = h1(x1)
     
     a(g(),x1) = 2x1 >= 2x1 = g1(x1)
    problem:
     f1(f1(x)) -> a(x,x)
     a(h(),x1) -> h1(x1)
     a(g(),x1) -> g1(x1)
    Matrix Interpretation Processor: dim=1
     
     interpretation:
      [g1](x0) = 3x0,
      
      [h1](x0) = 3x0,
      
      [f1](x0) = 2x0,
      
      [g] = 1,
      
      [h] = 0,
      
      [a](x0, x1) = x0 + 3x1
     orientation:
      f1(f1(x)) = 4x >= 4x = a(x,x)
      
      a(h(),x1) = 3x1 >= 3x1 = h1(x1)
      
      a(g(),x1) = 3x1 + 1 >= 3x1 = g1(x1)
     problem:
      f1(f1(x)) -> a(x,x)
      a(h(),x1) -> h1(x1)
     Matrix Interpretation Processor: dim=1
      
      interpretation:
       [h1](x0) = 3x0,
       
       [f1](x0) = 2x0,
       
       [h] = 1,
       
       [a](x0, x1) = x0 + 3x1
      orientation:
       f1(f1(x)) = 4x >= 4x = a(x,x)
       
       a(h(),x1) = 3x1 + 1 >= 3x1 = h1(x1)
      problem:
       f1(f1(x)) -> a(x,x)
      Matrix Interpretation Processor: dim=1
       
       interpretation:
        [f1](x0) = 2x0 + 5,
        
        [a](x0, x1) = 2x0 + x1
       orientation:
        f1(f1(x)) = 4x + 15 >= 3x = a(x,x)
       problem:
        
       Qed