MAYBE

Problem:
 f(s(x),x) -> f(s(x),round(s(x)))
 round(0()) -> 0()
 round(0()) -> s(0())
 round(s(0())) -> s(0())
 round(s(s(x))) -> s(s(round(x)))

Proof:
 DP Processor:
  DPs:
   f#(s(x),x) -> round#(s(x))
   f#(s(x),x) -> f#(s(x),round(s(x)))
   round#(s(s(x))) -> round#(x)
  TRS:
   f(s(x),x) -> f(s(x),round(s(x)))
   round(0()) -> 0()
   round(0()) -> s(0())
   round(s(0())) -> s(0())
   round(s(s(x))) -> s(s(round(x)))
  Usable Rule Processor:
   DPs:
    f#(s(x),x) -> round#(s(x))
    f#(s(x),x) -> f#(s(x),round(s(x)))
    round#(s(s(x))) -> round#(x)
   TRS:
    round(s(0())) -> s(0())
    round(s(s(x))) -> s(s(round(x)))
    round(0()) -> 0()
    round(0()) -> s(0())
   Open