YES

Problem:
 if(if(x,y,z),u,v) -> if(x,if(y,u,v),if(z,u,v))

Proof:
 DP Processor:
  DPs:
   if#(if(x,y,z),u,v) -> if#(z,u,v)
   if#(if(x,y,z),u,v) -> if#(y,u,v)
   if#(if(x,y,z),u,v) -> if#(x,if(y,u,v),if(z,u,v))
  TRS:
   if(if(x,y,z),u,v) -> if(x,if(y,u,v),if(z,u,v))
  KBO Processor:
   argument filtering:
    pi(if) = [0,1,2]
    pi(if#) = 0
   usable rules:
    
   weight function:
    w0 = 1
    w(if#) = w(if) = 1
   precedence:
    if# ~ if
   problem:
    DPs:
     
    TRS:
     if(if(x,y,z),u,v) -> if(x,if(y,u,v),if(z,u,v))
   Qed