MAYBE

Problem:
 f() -> b()
 b() -> f()

Proof:
 DP Processor:
  DPs:
   f#() -> b#()
   b#() -> f#()
  TRS:
   f() -> b()
   b() -> f()
  Usable Rule Processor:
   DPs:
    f#() -> b#()
    b#() -> f#()
   TRS:
    
   Open