MAYBE

Problem:
 f(f(s(x),0()),f(y,z)) -> f(f(y,z),f(y,s(z)))
 f(f(s(x),s(y)),f(z,w)) -> f(f(x,y),f(z,w))

Proof:
 DP Processor:
  DPs:
   f#(f(s(x),0()),f(y,z)) -> f#(y,s(z))
   f#(f(s(x),0()),f(y,z)) -> f#(f(y,z),f(y,s(z)))
   f#(f(s(x),s(y)),f(z,w)) -> f#(x,y)
   f#(f(s(x),s(y)),f(z,w)) -> f#(f(x,y),f(z,w))
  TRS:
   f(f(s(x),0()),f(y,z)) -> f(f(y,z),f(y,s(z)))
   f(f(s(x),s(y)),f(z,w)) -> f(f(x,y),f(z,w))
  Open