YES

Problem:
 minus(0()) -> 0()
 +(x,0()) -> x
 +(0(),y) -> y
 +(minus(1()),1()) -> 0()
 minus(minus(x)) -> x
 +(x,minus(y)) -> minus(+(minus(x),y))
 +(x,+(y,z)) -> +(+(x,y),z)
 +(minus(+(x,1())),1()) -> minus(x)

Proof:
 DP Processor:
  DPs:
   +#(x,minus(y)) -> minus#(x)
   +#(x,minus(y)) -> +#(minus(x),y)
   +#(x,minus(y)) -> minus#(+(minus(x),y))
   +#(x,+(y,z)) -> +#(x,y)
   +#(x,+(y,z)) -> +#(+(x,y),z)
   +#(minus(+(x,1())),1()) -> minus#(x)
  TRS:
   minus(0()) -> 0()
   +(x,0()) -> x
   +(0(),y) -> y
   +(minus(1()),1()) -> 0()
   minus(minus(x)) -> x
   +(x,minus(y)) -> minus(+(minus(x),y))
   +(x,+(y,z)) -> +(+(x,y),z)
   +(minus(+(x,1())),1()) -> minus(x)
  Matrix Interpretation Processor: dim=1
   
   usable rules:
    minus(0()) -> 0()
    +(x,0()) -> x
    +(0(),y) -> y
    +(minus(1()),1()) -> 0()
    minus(minus(x)) -> x
    +(x,minus(y)) -> minus(+(minus(x),y))
    +(x,+(y,z)) -> +(+(x,y),z)
    +(minus(+(x,1())),1()) -> minus(x)
   interpretation:
    [+#](x0, x1) = x0 + 4x1 + 7,
    
    [minus#](x0) = x0 + 2,
    
    [1] = 1,
    
    [+](x0, x1) = x0 + 4x1 + 5,
    
    [minus](x0) = x0 + 1,
    
    [0] = 6
   orientation:
    +#(x,minus(y)) = x + 4y + 11 >= x + 2 = minus#(x)
    
    +#(x,minus(y)) = x + 4y + 11 >= x + 4y + 8 = +#(minus(x),y)
    
    +#(x,minus(y)) = x + 4y + 11 >= x + 4y + 8 = minus#(+(minus(x),y))
    
    +#(x,+(y,z)) = x + 4y + 16z + 27 >= x + 4y + 7 = +#(x,y)
    
    +#(x,+(y,z)) = x + 4y + 16z + 27 >= x + 4y + 4z + 12 = +#(+(x,y),z)
    
    +#(minus(+(x,1())),1()) = x + 21 >= x + 2 = minus#(x)
    
    minus(0()) = 7 >= 6 = 0()
    
    +(x,0()) = x + 29 >= x = x
    
    +(0(),y) = 4y + 11 >= y = y
    
    +(minus(1()),1()) = 11 >= 6 = 0()
    
    minus(minus(x)) = x + 2 >= x = x
    
    +(x,minus(y)) = x + 4y + 9 >= x + 4y + 7 = minus(+(minus(x),y))
    
    +(x,+(y,z)) = x + 4y + 16z + 25 >= x + 4y + 4z + 10 = +(+(x,y),z)
    
    +(minus(+(x,1())),1()) = x + 19 >= x + 1 = minus(x)
   problem:
    DPs:
     
    TRS:
     minus(0()) -> 0()
     +(x,0()) -> x
     +(0(),y) -> y
     +(minus(1()),1()) -> 0()
     minus(minus(x)) -> x
     +(x,minus(y)) -> minus(+(minus(x),y))
     +(x,+(y,z)) -> +(+(x,y),z)
     +(minus(+(x,1())),1()) -> minus(x)
   Qed