MAYBE

Problem:
 f(y,f(x,f(a(),x))) -> f(f(a(),f(x,a())),f(a(),y))
 f(x,f(x,y)) -> f(f(f(x,a()),a()),a())

Proof:
 DP Processor:
  DPs:
   f#(y,f(x,f(a(),x))) -> f#(a(),y)
   f#(y,f(x,f(a(),x))) -> f#(x,a())
   f#(y,f(x,f(a(),x))) -> f#(a(),f(x,a()))
   f#(y,f(x,f(a(),x))) -> f#(f(a(),f(x,a())),f(a(),y))
   f#(x,f(x,y)) -> f#(x,a())
   f#(x,f(x,y)) -> f#(f(x,a()),a())
   f#(x,f(x,y)) -> f#(f(f(x,a()),a()),a())
  TRS:
   f(y,f(x,f(a(),x))) -> f(f(a(),f(x,a())),f(a(),y))
   f(x,f(x,y)) -> f(f(f(x,a()),a()),a())
  Open