MAYBE

Problem:
 a(b(x1)) -> b(b(b(b(x1))))
 b(a(x1)) -> a(a(a(a(x1))))
 a(x1) -> x1
 b(x1) -> x1

Proof:
 DP Processor:
  DPs:
   a#(b(x1)) -> b#(b(x1))
   a#(b(x1)) -> b#(b(b(x1)))
   a#(b(x1)) -> b#(b(b(b(x1))))
   b#(a(x1)) -> a#(a(x1))
   b#(a(x1)) -> a#(a(a(x1)))
   b#(a(x1)) -> a#(a(a(a(x1))))
  TRS:
   a(b(x1)) -> b(b(b(b(x1))))
   b(a(x1)) -> a(a(a(a(x1))))
   a(x1) -> x1
   b(x1) -> x1
  Open