MAYBE

Problem:
 f(X,X) -> f(a(),n__b())
 b() -> a()
 b() -> n__b()
 activate(n__b()) -> b()
 activate(X) -> X

Proof:
 DP Processor:
  DPs:
   f#(X,X) -> f#(a(),n__b())
   activate#(n__b()) -> b#()
  TRS:
   f(X,X) -> f(a(),n__b())
   b() -> a()
   b() -> n__b()
   activate(n__b()) -> b()
   activate(X) -> X
  Usable Rule Processor:
   DPs:
    f#(X,X) -> f#(a(),n__b())
    activate#(n__b()) -> b#()
   TRS:
    
   Open