MAYBE

Problem:
 a(x1) -> x1
 a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
 b(x1) -> a(x1)

Proof:
 DP Processor:
  DPs:
   a#(a(b(a(x1)))) -> a#(a(x1))
   a#(a(b(a(x1)))) -> a#(a(a(x1)))
   a#(a(b(a(x1)))) -> b#(a(a(a(x1))))
   a#(a(b(a(x1)))) -> b#(b(a(a(a(x1)))))
   b#(x1) -> a#(x1)
  TRS:
   a(x1) -> x1
   a(a(b(a(x1)))) -> b(b(a(a(a(x1)))))
   b(x1) -> a(x1)
  Open