MAYBE

Problem:
 f(f(a(),a()),x) -> f(x,f(a(),f(a(),a())))

Proof:
 DP Processor:
  DPs:
   f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
   f#(f(a(),a()),x) -> f#(x,f(a(),f(a(),a())))
  TRS:
   f(f(a(),a()),x) -> f(x,f(a(),f(a(),a())))
  Usable Rule Processor:
   DPs:
    f#(f(a(),a()),x) -> f#(a(),f(a(),a()))
    f#(f(a(),a()),x) -> f#(x,f(a(),f(a(),a())))
   TRS:
    
   Open