MAYBE

Problem:
 a(b(c(x1))) -> c(c(b(b(a(a(x1))))))
 a(x1) -> x1
 b(x1) -> x1
 c(x1) -> x1

Proof:
 DP Processor:
  DPs:
   a#(b(c(x1))) -> a#(x1)
   a#(b(c(x1))) -> a#(a(x1))
   a#(b(c(x1))) -> b#(a(a(x1)))
   a#(b(c(x1))) -> b#(b(a(a(x1))))
   a#(b(c(x1))) -> c#(b(b(a(a(x1)))))
   a#(b(c(x1))) -> c#(c(b(b(a(a(x1))))))
  TRS:
   a(b(c(x1))) -> c(c(b(b(a(a(x1))))))
   a(x1) -> x1
   b(x1) -> x1
   c(x1) -> x1
  Open