Tool Bounds
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ check(cons(x, y)) -> cons(x, y)
, check(cons(x, y)) -> cons(x, check(y))
, check(cons(x, y)) -> cons(check(x), y)
, check(rest(x)) -> rest(check(x))
, check(sent(x)) -> sent(check(x))
, rest(cons(x, y)) -> sent(y)
, rest(nil()) -> sent(nil())
, top(sent(x)) -> top(check(rest(x)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool CDI
stdout:
MAYBE
Statistics:
Number of monomials: 381
Last formula building started for bound 3
Last SAT solving started for bound 3Tool EDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ check(cons(x, y)) -> cons(x, y)
, check(cons(x, y)) -> cons(x, check(y))
, check(cons(x, y)) -> cons(check(x), y)
, check(rest(x)) -> rest(check(x))
, check(sent(x)) -> sent(check(x))
, rest(cons(x, y)) -> sent(y)
, rest(nil()) -> sent(nil())
, top(sent(x)) -> top(check(rest(x)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool IDA
stdout:
TIMEOUT
We consider the following Problem:
Strict Trs:
{ check(cons(x, y)) -> cons(x, y)
, check(cons(x, y)) -> cons(x, check(y))
, check(cons(x, y)) -> cons(check(x), y)
, check(rest(x)) -> rest(check(x))
, check(sent(x)) -> sent(check(x))
, rest(cons(x, y)) -> sent(y)
, rest(nil()) -> sent(nil())
, top(sent(x)) -> top(check(rest(x)))}
StartTerms: all
Strategy: none
Certificate: TIMEOUT
Proof:
Computation stopped due to timeout after 60.0 seconds.
Arrrr..Tool TRI
stdout:
YES(?,O(n^4))
We consider the following Problem:
Strict Trs:
{ check(cons(x, y)) -> cons(x, y)
, check(cons(x, y)) -> cons(x, check(y))
, check(cons(x, y)) -> cons(check(x), y)
, check(rest(x)) -> rest(check(x))
, check(sent(x)) -> sent(check(x))
, rest(cons(x, y)) -> sent(y)
, rest(nil()) -> sent(nil())
, top(sent(x)) -> top(check(rest(x)))}
StartTerms: all
Strategy: none
Certificate: YES(?,O(n^4))
Proof:
We have the following triangular matrix interpretation:
Interpretation Functions:
sent(x1) = [1 1 0 1 1] x1 + [0]
[0 1 0 3 0] [0]
[0 0 0 2 3] [1]
[0 0 0 1 0] [1]
[0 0 0 0 0] [0]
top(x1) = [1 0 2 0 0] x1 + [0]
[0 0 0 0 0] [1]
[0 0 0 0 0] [1]
[0 0 0 0 0] [1]
[0 0 0 0 0] [1]
rest(x1) = [1 0 0 0 2] x1 + [0]
[0 1 0 0 0] [1]
[0 0 1 0 3] [0]
[0 0 0 1 1] [0]
[0 0 0 0 0] [0]
check(x1) = [1 1 0 1 0] x1 + [0]
[0 1 0 0 0] [0]
[0 0 0 2 0] [0]
[0 0 0 1 0] [0]
[0 0 0 0 0] [0]
nil() = [0]
[0]
[1]
[0]
[1]
cons(x1, x2) = [1 0 0 0 3] x1 + [1 1 0 1 1] x2 + [1]
[0 1 0 3 0] [0 1 0 3 0] [0]
[0 0 0 0 0] [0 0 0 2 3] [1]
[0 0 0 1 1] [0 0 0 1 2] [2]
[0 0 0 0 0] [0 0 0 0 0] [0]
Hurray, we answered YES(?,O(n^4))Tool TRI2
stdout:
MAYBE
We consider the following Problem:
Strict Trs:
{ check(cons(x, y)) -> cons(x, y)
, check(cons(x, y)) -> cons(x, check(y))
, check(cons(x, y)) -> cons(check(x), y)
, check(rest(x)) -> rest(check(x))
, check(sent(x)) -> sent(check(x))
, rest(cons(x, y)) -> sent(y)
, rest(nil()) -> sent(nil())
, top(sent(x)) -> top(check(rest(x)))}
StartTerms: all
Strategy: none
Certificate: MAYBE
Proof:
The input cannot be shown compatible
Arrrr..